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4 years ago

What is the average acceleration? Please show work!

Physics

1 answer:

nignag [31]4 years ago

7 0

Answer:

Explanation:

Average acceleration

= (final velocity - initial velocity) /time

= (50-0)km/h /30 s

= 50 * 1000 / 3600 m/s /s

= 13.89 m/s^2

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A 96.0 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.240 m/s. How much work must be done on

Ede4ka [16]

Answer:

The work done by the hoop is equal to 5.529 Joules.

Explanation:

Given that,

Mass of the hoop, m = 96 kg

The speed of the center of mass, v = 0.24 m/s

To find,

The work done by the hoop.

Solution,

The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,

$K_i=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2$

I is the moment of inertia, $I=mr^2$

Since, $\omega=\dfrac{v}{r}$

$K_i=mv^2$

$K_i=96\times (0.24)^2=5.529\ J$

Finally it stops, so the final energy of the hoop will be, $K_f=0$

The work done by the hoop is equal to the change in kinetic energy as :

$W=K_f-K_i$

W = -5.529 Joules

So, the work done by the hoop is equal to 5.529 Joules. Therefore, this is the required solution.

4 0

3 years ago

Magnitude of force F experienced by a certain object moving with speed v is given by F=Kv race to 2, where K is constant. Find t

My name is Ann [436]

<h2>Answer:</h2>

MT⁻¹

<h2>Explanation:</h2>

Given equation:

F = Kv --------------(i)

Where;

F = Magnitude of force experienced by the object

v = speed at which the object is moving

K = constant.

To get the dimension of K, follow the following steps:

i. Make K subject of the formula in equation(i)

K = F / v

ii. Get the dimension of force F and speed v

Dimension of force = MLT⁻²

Dimension of velocity = LT⁻¹

iii. Substitute these dimensions into the result of (i) above;

K = MLT⁻² / LT⁻¹

iv. Simplify the result in (iii)

First, the Ls in the numerator and denominator will cancel out

K = MT⁻² / T⁻¹

Next, the Ts will be expressed as follows

K = MT⁻² x T¹ [using the law of indices]

K = MT⁻²⁺¹

K = MT⁻¹

Therefore, the dimension of K is MT⁻¹

6 0

3 years ago

The illustration shows the basic unit of life it is

vlabodo [156]

The answer is A, Cell. This is the basic structure of a cell.

6 0

3 years ago

Read 2 more answers

A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long

Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

$t = \frac{L}{v}$

$2.7 s = \frac{18}{v}$

$v = 6.67 m/s$

now we have

$v = \sqrt{\frac{T}{\lambda}}$

$6.67 = \sqrt{\frac{T}{0.67}}$

so we will have

$T = 29.6 N$

5 0

4 years ago

A neutral atom can be negatively charged by???

IRINA_888 [86]

Answer:

The answer to your question is below.

Explanation:

Atoms are composed by three different subparticles

- protons are small particles positive charged located in the nucleus.

- neutrons are small particles without a charged located in the nucleus.

- electrons are the smallest subparticles and are negatively charged.

In a neutral atom, the amount of positive charges (protons) is equal to the amount of negative charges (electrons) so it does not have any charge.

If a neutral atom gains one or more electrons it would be negative.

4 0

3 years ago