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laiz [17]
3 years ago
9

Two people, Micah and Lyra, with different near points are equally close to an object. Both inspect the object through the same

magnifier by holding the lens close to the eye. Micah's near point is located farther away from his eye than Lyra's near point is located relative to her eye.
Micah will experience a larger magnification for which of the following reasons?


a.When the object is located at his near point, the angular size of the object is smaller for Micah than for Lyra.

b.Micah sees a larger image than Lyra sees.

c.Micah can see the image clearly from a larger distance than Lyra can.

d.Lyra can see the image clearly from a larger distance than Micah can.

e.The angular size of the image relative to the angular size of the object at the near point is greater for Micah than for Lyra.
Physics
1 answer:
Gekata [30.6K]3 years ago
4 0
Meh kock is really really hard
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1.
drek231 [11]

Answer:

2500m

Explanation:

given,

initial velocity(u) = 5m/s

final velocity (v) = 0 m/s ( as he/she stopped riding after 1000 secs)

time = 1000 secs

distance(s)=?

now,

s=( u+v ) ×t /2

=(5+0)×1000/2

=2500 m

hence, he /she travels 2500m far

8 0
2 years ago
Mark was traveling at 40 mph on a road with a drag factor of 0.85. His brakes were working at B0o/o efficiency. To the nearest t
algol [13]

Answer:

PLS OPEN THE LINK FOR THE ANSWER

Explanation:

4 0
2 years ago
A semiconductor is a _____. a) crystalline solid that conducts current under any condition b) crystalline solid that conducts cu
max2010maxim [7]

Explanation:

A crystalline solid that conducts current under certain conditions

8 0
2 years ago
How does the magnetic force exerted by a magnet change as the distance between two magnets increases
hodyreva [135]
As the distance increases, their magnetic force decreases....
7 0
2 years ago
Calculate the Engineering Ultimate Tensile Strength and the maximum load in tension testing of an annealed copper specimen with
Natasha_Volkova [10]

Answer:

Explanation:

Original diameter = 5mm

d= 0.005m. r=0.0025m

True stress (σ) = 290MPa

Coefficient of annealing copper (n)=0.5

True stress is given as force/area

σ=F/A

Ao=πr^2

Ao=1.963×10^-5m2

F=σ ×A

F=290×10^6 ×π×(0.0025)^2

F= 5694.13N

Given that

σ=Kε^n

290=Kε^0.5

n=ε=0.5 at necking

Therefore

290=K×0.5^0.5

K=410.12MPa

ε=In(Ao/A)

0.5=In(π×0.0025^2/A)

exp(0.5)=1.96×10^-5/A

A=1.96×10^-5/exp(0.5)

A= 1.2×10^-5m2

This is the new area

Then the Ultimate Tensile Stress

σ=F/A

σ=5694.13/1.2×10^-5

σ=4.75×10^8Pa

σ=475MPa

Therefore,

The ultimate tensile stress is 475MPa.

The maximum tension is

Fo/Ao=F/A

F=(Fo/Ao) ×A

F=(5694.13/1963×10^-5)×1.2×10^-5

F= 3479.99

F=3480N.

3 0
3 years ago
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