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grigory [225]
3 years ago
5

Magnitude of force F experienced by a certain object moving with speed v is given by F=Kv race to 2, where K is constant. Find t

he dimension of K
Physics
1 answer:
My name is Ann [436]3 years ago
6 0
<h2>Answer:</h2>

MT⁻¹

<h2>Explanation:</h2>

Given equation:

F = Kv        --------------(i)

Where;

F = Magnitude of force experienced by the object

v = speed at which the object is moving

K = constant.

To get the dimension of K, follow the following steps:

i. <em>Make K subject of the formula in equation(i)</em>

K = F / v

ii.<em> Get the dimension of force F and speed v</em>

Dimension of force = MLT⁻²

Dimension of velocity = LT⁻¹

iii.<em> Substitute these dimensions into the result of (i) above;</em>

K = MLT⁻² / LT⁻¹

iv. <em>Simplify the result in (iii)</em>

<em>First, the </em><em>L</em><em>s in the numerator and denominator will cancel out</em>

K = MT⁻² / T⁻¹

<em>Next, the </em><em>T</em><em>s will be expressed as follows</em>

K = MT⁻² x T¹           [using the law of indices]

K = MT⁻²⁺¹

K = MT⁻¹

Therefore, the dimension of K is MT⁻¹

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yawa3891 [41]

Answer:

30.5 x 10³ min.

Explanation:

Atomic weight of aluminium = 27

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Now Charge  = Current x time

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4 years ago
A sealed tank containing seawater to a height of 12.8 m also contains air above the water at a gauge pressure of 2.90 atm . Wate
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Answer:

The velocity of water at the bottom, v_{b} = 28.63 m/s

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Height of water in the tank, h = 12.8 m

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Atmospheric pressue, P_{atm} = 1 atm = 1.01\tiems 10^{5} Pa

At the top, the absolute pressure, P_{t} = P_{gauge} + P_{atm} = 2.90 + 1 = 3.90 atm = 3.94\times 10^{5} Pa

Now, the pressure at the bottom will be equal to the atmopheric pressure, P_{b} = 1 atm = 1.01\times 10^{5} Pa

The velocity at the top, v_{top} = 0 m/s, l;et the bottom velocity, be v_{b}.

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4 years ago
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Answer:

Explanation:

Given

radius r=2.96 mm

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