A child on a bridge throws a rock straight down to the water below. The point where the child released the rock is 82 m above th
e water and it took 1.3 s for the rock to reach the water. Determine the rock's velocity (magnitude
1 answer:
Answer:
40 m/s
Explanation:
given,
height of the fall, h = 82 m
time taken to fall, t = 1.3 s
rock velocity, v = ?
acceleration due to gravity, g = 9.8 m/s²
rock is released initial velocity, u = 0 m/s
using equation of motion
v² = u² + 2 a s
v² = 0 + 2 x 9.8 x 82
v² = 1607.2
v = 40 m/s
hence, rock's velocity is equal to 40 m/s
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