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storchak [24]
3 years ago
12

A body is found in the woods and all you have left to analyze are bones and teeth. Explain what isotopes would be helpful to you

as you seek to identify these remains and match them to a missing person's report. How would these isotopes help in the identification of this person?
Physics
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

The isotopes that would be helpful to identify a missing person and complete its report are the stable isotopes.

The stable isotope forensic science analysis using Sr, O and S isotope variations has been developed recently using hair strands to identify recent geographic hints as temperature in climate causes the isotopes ratio to vary indicating if the person changed its geographic area or he/she  belongs to the area it was found, for what it drank.

Explanation:

The forensic analytical science uses different isotope´s methods like gas or liquid chromatography, HPLC, mass spectrometry, immunoassays, enzymatic assays, DNA profiling techniques, PCR, biosensing, metabolomics and LC-MS which can stablish the chemical nature of most of the samples provided.

As a basic principle consider isotopes are atoms of the same element that have different quantity of neutrons but the same number of protons and electrons.

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Ultraviolet light causes production of vitamin d3 in the cells of the __________.
dedylja [7]

Answer:

Epidermis

Explanation:

The epidermis is an important layer forming the skin that is mainly responsible for providing protection from the incoming harmful solar radiations, that are comprised of ultraviolet particles. These UV rays can cause various diseases like skin cancer.

When the solar radiations containing UV radiations (mostly the UV-B type radiation having a wavelength 290-315 nanometer) strikes the cells of human beings, then the protein that is stored within the skin named '7- dehydrocholesterolit (DHC)' is transformed into the vitamin d3 inside the cells.

4 0
3 years ago
A piston of volume 0.1 m3 contains two moles of a monatomic ideal gas at 300K. If it undergoes an isothermal process and expands
seropon [69]

Answer:

the work is done by the gas on the environment -is W= - 3534.94 J (since the initial pressure is lower than the atmospheric pressure , it needs external work to expand)

Explanation:

assuming ideal gas behaviour of the gas , the equation for ideal gas is

P*V=n*R*T

where

P = absolute pressure

V= volume

T= absolute temperature

n= number of moles of gas

R= ideal gas constant = 8.314 J/mol K

P=n*R*T/V

the work that is done by the gas is calculated through

W=∫pdV=  ∫ (n*R*T/V) dV

for an isothermal process T=constant and since the piston is closed vessel also n=constant during the process then denoting 1 and 2 for initial and final state respectively:

W=∫pdV=  ∫ (n*R*T/V) dV =  n*R*T  ∫(1/V) dV = n*R*T * ln (V₂/V₁)

since

P₁=n*R*T/V₁

P₂=n*R*T/V₂

dividing both equations

V₂/V₁ = P₁/P₂

W= n*R*T * ln (V₂/V₁)  = n*R*T * ln (P₁/P₂ )

replacing values

P₁=n*R*T/V₁ = 2 moles* 8.314 J/mol K* 300K / 0.1 m3= 49884 Pa

since P₂ = 1 atm = 101325 Pa

W= n*R*T * ln (P₁/P₂ ) = 2 mol * 8.314 J/mol K * 300K * (49884 Pa/101325 Pa) = -3534.94 J

5 0
3 years ago
which best describes what happens with the sonar to sound pulses from a ship after they hit the ocean floor?
lakkis [162]

Answer:

With sonar, what happens to sound pulses from a ship after they hit the ocean floor? ... They bounce back to the ship.

Explanation:

3 0
3 years ago
In a nuclear physics experiment, a proton (mass 1.67×10^(−27)kg, charge +e=+1.60×10^(−19)C) is fired directly at a target nucleu
Arte-miy333 [17]

The given question is incomplete. The complete question is as follows.

In a nuclear physics experiment, a proton (mass 1.67 \times 10^(-27)kg, charge +e = +1.60 \times 10^(-19) C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed 2.50 \times 10^6 m/s. The proton comes momentarily to rest at a distance 5.31 \times 10^(-13) m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are 5.31 \times 10^{-13} m apart?

Explanation:

The given data is as follows.

Mass of proton = 1.67 \times 10^{-27} kg

Charge of proton = 1.6 \times 10^{-19} C

Speed of proton = 2.50 \times 10^{6} m/s

Distance traveled = 5.31 \times 10^{-13} m

We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.

  (K.E + P.E)_{initial} = (K.E + P.E)_{final}

 (\frac{1}{2} m_{p}v^{2}_{p}) = (\frac{kq_{p}q_{t}}{r} + 0)

where,    \frac{kq_{p}q_{t}}{r} = U = Electric potential energy

     U = (\frac{1}{2}m_{p}v^{2}_{p})

Putting the given values into the above formula as follows.

        U = (\frac{1}{2}m_{p}v^{2}_{p})

            = (\frac{1}{2} \times 1.67 \times 10^{-27} \times (2.5 \times 10^{6})^{2})

            = 5.218 \times 10^{-15} J

Therefore, we can conclude that the electric potential energy of the proton and nucleus is 5.218 \times 10^{-15} J.

4 0
3 years ago
If a bat hits a ball with a 1000-N force, what force does the ball exert on the bat?
scoundrel [369]
Same magnitude (1000N) and opposite direction 
you may also answer -1000 N
4 0
3 years ago
Read 2 more answers
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