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frozen [14]
3 years ago
11

A small object carrying a charge of -3.00 nc is acted upon by a downward force of 30.0 nn when placed at a certain point in an e

lectric field.
Physics
1 answer:
arlik [135]3 years ago
3 0
The working equation for this one is:

E = F/Q, where E is the strength of the electric field, F is the electric force and Q is the charge. Substituting the corresponding values, the strength of the electric field is equal to

E = -30 nN/-3 nC
E = 10 nN/nC


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t=\sqrt{\frac{2(0.75m)}{5.88m/{s}^{2}}}   (12)

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If V_{o}=0

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