Answer:
The intensity of light emerging from the second polarizer is zero.
Explanation:
The angle between the axis of first polarizer and the second polarizer is 90°.
According to the law of Malus
![I = I_{0}\times Cos^{2}\Theta](https://tex.z-dn.net/?f=I%20%3D%20I_%7B0%7D%5Ctimes%20Cos%5E%7B2%7D%5CTheta)
where,
be the intensity of incident light on first polarizer and I be the intensity of light emerging out from second polarizer.
The intensity of light emerging out from first polarizer is given by
![I_{1}=\frac{I_{0}}{2}](https://tex.z-dn.net/?f=I_%7B1%7D%3D%5Cfrac%7BI_%7B0%7D%7D%7B2%7D)
the inetnsity of light emerging out from second polarizer is given by
![I = I_{1}\times Cos^{2}90](https://tex.z-dn.net/?f=I%20%3D%20I_%7B1%7D%5Ctimes%20Cos%5E%7B2%7D90)
![I = 0](https://tex.z-dn.net/?f=I%20%3D%200)
Thus, no light waves are emerging out from the second polarizer.