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ASHA 777 [7]
3 years ago
15

light incident on a polarizer is then passed through a second polarizer. if the polarizer and the analyzer are perpendicular to

each other, what can you say about the light waves emerging from the second polarizer?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
Physics
2 answers:
Lerok [7]3 years ago
8 0
<span>Indeed, this is one of the odd results in physics. A system of two polarizing filters arranged as shown below trasmits no light.</span>
rewona [7]3 years ago
8 0

Answer:

The intensity of light emerging from the second polarizer is zero.

Explanation:

The angle between the axis of first polarizer and the second polarizer is 90°.

According to the law of Malus

I = I_{0}\times Cos^{2}\Theta

where, I_{0} be the intensity of incident light on first polarizer and I be the intensity of light emerging out from second polarizer.

The intensity of light emerging out from first polarizer is given by

I_{1}=\frac{I_{0}}{2}

the inetnsity of light emerging out from second polarizer is given by

I = I_{1}\times Cos^{2}90

I = 0

Thus, no light waves are emerging out from the second polarizer.

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From the second law of motion:

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A fan that is rotating at 960 rev/s is turned off. It makes 1500 revolutions before it comes to a stop. a) What was its angular
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Explanation:

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ωi = initial angular speed = (960 rev/s)(2π rad/1 rev) = 6031.87 rad/s

Therefore,

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