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ASHA 777 [7]
3 years ago
15

light incident on a polarizer is then passed through a second polarizer. if the polarizer and the analyzer are perpendicular to

each other, what can you say about the light waves emerging from the second polarizer?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
Physics
2 answers:
Lerok [7]3 years ago
8 0
<span>Indeed, this is one of the odd results in physics. A system of two polarizing filters arranged as shown below trasmits no light.</span>
rewona [7]3 years ago
8 0

Answer:

The intensity of light emerging from the second polarizer is zero.

Explanation:

The angle between the axis of first polarizer and the second polarizer is 90°.

According to the law of Malus

I = I_{0}\times Cos^{2}\Theta

where, I_{0} be the intensity of incident light on first polarizer and I be the intensity of light emerging out from second polarizer.

The intensity of light emerging out from first polarizer is given by

I_{1}=\frac{I_{0}}{2}

the inetnsity of light emerging out from second polarizer is given by

I = I_{1}\times Cos^{2}90

I = 0

Thus, no light waves are emerging out from the second polarizer.

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Determine the total moment of inertia of a merry-go round with 5 children sitting on it. Of the five children, four are seated a
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Answer:

Explanation:

Given that,

We have five children.

Each of mass m =30kg

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Mass of Merry go round M= 150kg

Radius of Merry go round is r =2m

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The four child that sit at the edge are 2m from the centre of the merry go round but the one at the centre is 0m from the centre

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Moment of inertia is given as

I=Σmi•ri²

For the question, the moment of inertia is the combination of inertial of child and the merry go round

I= I(merry go round) + I(four child)+ I(last child)

The merry go round is assumed to be a solid cylinder, so it is going to have the moment of inertia of solid cylinder

Then,

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I= I(merry go round) + I(four child) +I(last child )

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I = ½ × 150 ×2² + 4×30×2² + 30×0²

I = 300 +480+0

I = 780 kgm²

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