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3 years ago

Fertilization takes place when

Chemistry

2 answers:

Marat540 [252]3 years ago

3 0

I believe the answer is C. let me know if this helped.

coldgirl [10]3 years ago

3 0

D is your answer . hope it helps

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The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon

xenn [34]

<u>Answer:</u> The percent composition of $Fe_3O_4$ in taconite is 37.6 %.

<u>Explanation:</u>

We are given:

Mass of taconite pellets = 1 ton = 907185 g (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g (Conversion factor: 1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of $Fe_3O_4$ = 231.53 g/mol

1 mole of $Fe_3O_4$ contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of $Fe_3O_4$

So, 247212 grams of iron will be produced from = $\frac{231.53}{167.55}\times 247212=341611.43g$ of $Fe_3O_4$

To calculate the percentage of $Fe_3O_4$ in taconite, we use the equation:

$\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100$

Mass of taconite = 907185 g

Mass of $Fe_3O_4$ = 341611.43 g

Putting values in above equation, we get:

$\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%$

Hence, the percent composition of $Fe_3O_4$ in taconite is 37.6 %.

8 0

3 years ago

Determine the volume in mL of 0.242 M NaOH(aq) needed to reach the equivalence (stoichiometric) point in the titration of 46.79

Alla [95]

The volume (in mL) of 0.242 M NaOH solution needed for the titration reaction is 39.44 mL

<h3>Balanced equation </h3>

CH₃CH₂COOH + NaOH —> CH₃CH₂COONa + H₂O

From the balanced equation above,

The mole ratio of the acid, CH₃CH₂COOH (nA) = 1
The mole ratio of the base, NaOH (nB) = 1

<h3>How to determine the volume of NaOH</h3>

Volume of acid, CH₃CH₂COOH (Va) = 46.79 mL
Molarity of acid, CH₃CH₂COOH (Ma) = 0.204 M
Molarity of base, NaOH (Mb) = 0.242 M

Volume of base, KOH (Vb) =?

MaVa / MbVb = nA / nB

(0.204 × 46.79) / (0.242 × Vb) = 1

Cross multiply

0.242 × Vb = 0.204 × 46.79

Divide both side by 0.242

Vb = (0.204 × 46.79) / 0.242

Vb = 39.44 mL

Thus, the volume of NaOH needed for the reaction is 39.44 mL

Learn more about titration:

brainly.com/question/14356286

5 0

2 years ago

Summarize the weather conditions related to a cold front. Remember to include all data collected on cold fronts in this activity

svp [43]

Answer: Many fronts cause weather events such as rain, thunderstorms, gusty winds and A weather front is a transition zone between two different air masses at the Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds

Explanation:

Hope this was helpful

5 0

2 years ago

8.310x10^2 – 7.210x10^1<br><br>[?]x10^[?]

alisha [4.7K]

Answer:

$7.589\times 10^{2}$

Explanation:

The expression can be solved mathematically as follows:

1) $8.310\times 10^{2}-7.210\times 10^{1}$ Given

2) $8.310\times 10^{1+1} - 7.210\times 10^{1}$ Definition of sum

3) $(8.310\times 10^{1})\times 10^{1}-7.210\times 10^{1}$ $a^{m+n} = a^{m}\cdot a^{n}$ /Associative property

4) $(8.310\times 10^{1}-7.210)\times 10^{1}$ Distributive property

5) $(83.100-7.210)\times 10^{1}$ Multiplication

6) $75.89\times 10^{1}$ Subtraction.

7) $(7.589\times 10^{1})\times 10^{1}$ Multiplication/Associative property

8) $7.589\times (10^{1}\times 10^{1})$ Associative property

9) $7.589\times 10^{2}$ $a^{m+n} = a^{m}\cdot a^{n}$ /Result

7 0

3 years ago

What must happen for an igneous rock to form

Ksenya-84 [330]

Answer:

Igneous Rocks: form by crystallizing melted material (magma).

Explanation:

They can form either on the surface (extrusive igneous rocks), or deep in the crust (intrusive or plutonic igneous rocks).

4 0

2 years ago