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Marina86 [1]
3 years ago
9

Which choice gives the correct oxidation numbers for all three elements in rb2so3 in the order that the elements are shown in th

e formula?
Chemistry
1 answer:
vlabodo [156]3 years ago
7 0
<h3>Answer:</h3>

             Rb  =  + 1

              S    =  + 4

              O   =  - 2

<h3>Explanation:</h3>

                   Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,

Rb₂ + S + O₃  =  0

Above zero (0) means that the overall molecule is neutral.

Putting values of Rb and O,

                                           (+1)₂ + S + (-2)₃  =  0

                                           (+2) + S + (-6)  =  0

                                           +2 + S - 6  = 0

                                           S - 6  =  -2

                                          S  =  -2 + 6

                                           S  =  + 4

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Answer:

                  P  =  0.0009417 atm

Or,

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Or,

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Or,

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Explanation:

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                 Temperature  =  T  =  312 K

                  Pressure  =  P  =  ?

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Formula Used:

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                  P V  =  n R T

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Solving Equation for P,

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                 P  =  9.417 × 10⁻⁴ atm

Or,

                  P  =  0.0954157 kPa

Or,

                  P  =  0.715677 mmHg (Torr)

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