The mass of plutonium that will remain after 1000 years if the initial amount is 5 g when the half life of plutonium-239 (239pu, pu-239) is 24,100 years is 2.5 g
The equation is Mr=Mi(1/2)^n
where n is the number of half-lives
Mr is the mass remaining after n half lives
Mi is the initial mass of the sample
To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)
n=1000/24100=0.0414
So Mr=5x(1/2)^1=2.5 g
The mass remaining is 2.5 g
- The half life is the time in which the concentration of a substance decreases to half of the initial value.
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B; Seismometer would be the answer.
Answer:
Coefficient's are 2, 2, 1
Explanation:
We are given;
Unbalanced equation;
H₂O₂ → H₂O + O₂
We are required to determine the suitable coefficients that would balance the equation.
- We need to know that for an equation to obey the law of conservation of mass it has to be balanced.
- Balancing involves making sure that the number of atoms of each element are equal on both sides of the equation.
In this case;
To balance the equation we put the coefficients 2, 2, 1 respectively
Therefore;
The balanced equation is;
2H₂O₂ → 2H₂O + O₂
Thus, Suitable coefficients are, 2, 2, 1
I believe that the answer is A. Decaying
