Rubidium would exhibit the greatest shielding [ effect. ]
Answer: C REDUCTION
Explanation:
Guessed after knowing oxidation isn't the answer. Got right
The Orbital configuration for Manganese is as follows:
1s2 2s2 2p6 3s2 3p6 4s2 3d5
It says 3d is shown with five orbitals- this is correct
Then it says the first two orbitals have two electrons-this is incorrect.
When filling in the orbitals for any element, you first need to distribute to ALL orbitals then extras go from there.
The orbital d can have up to 10 electrons so you need to distribute at least one electron to all ten. Since you only have 5 then only 5 orbitals would have electrons in them. In order for ANY of the orbitals to have two electrons, there would need to be AT LEAST 11 electrons to distribute.
Answer:
318.749g
Explanation:
The find the mass,
We use this formula
Number of mole = mass/ molar mass
Since number of mole = 3.25mol
Let the number of mass be x
The molar mass of H2SO4
H - 1.00784 * 2= 2.01568
S - 32.065
O - 15.999 * 4 = 63.996
Note there are 2 moles of H and 4 moles of O and 1 mole of S
Molar mass of H2SO4 = 2.01568 + 32.065 + 63.996
= 98.07668g/mol
Number of mole= 3.25mol
3.25 = x / 98.07668
x = 3.25 * 98.07668
x= 318.749g
Hence, the number of mass is 318.749g
Hope it will help you.
