Answer:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
Explanation:
Sodium is present in group 1.
It is alkali metal.
It has one valence electron.
The atomic number of sodium is 11.
Its atomic mass is 23 amu.
The longhand notation of electronic configuration of sodium can be written as,
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
The electronic configuration in shorthand notation( noble gas) would be written as,
Na₁₁ = [Ne] 3s¹
Sodium loses its one valence electron to complete the octet and get stable thus form +1 cation.
It react with halogen and form salt. Such as sodium chloride.
2Na + Cl₂ → 2NaCl
dish Soap,Corn Syrup,Rubbing Alcohol, Milk,
Answer:
The correct options are;
C. The magnitude of attraction from its nucleus
D. The distance between the electrons and its nucleus
Explanation:
The atomic radius reduces, within a given period, as we move from left to right, the number of protons increases alongside the number of electrons and the while the quantum shell to which the extra electrons are added to is the same. Therefore, the radius of the atom is dependent on the magnitude of the attraction from the nucleus
Similarly, as we progress to the next period, with an extra quantum shell, the atomic radius is seen to increase.
Therefore, the atomic radius is determined by the distance between the electrons and its nucleus.
Answer:option A
Multiple reactants are used to form one product.
Answer:
carbon because organic compounds are made up of hydrogen and carbon
