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3 years ago

3. Solve the equation| 3x - 1| + 5 = 3

Mathematics

2 answers:

zaharov [31]3 years ago

4 0

No solution! .. no x values to make the equation true

nalin [4]3 years ago

3 0

Answer:

Its not possible

Step-by-step explanation:

a absolute value equation cant equal a negative number

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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

What is 7^5 equal to

Alona [7]

The answer to 7^5 = 16807

5 0

3 years ago

Can someone help me with this graph please

Veronika [31]

These are the answers to your questions

a.In short supply
b.5
c.5

8 0

2 years ago

What is the equation in slope-intercept form of a line that is perpendicular to y=2x+2 and passes through the point (4, 3)?

Ostrovityanka [42]

<h2>Answer: y = - ¹/₂ x + 5 </h2>

<h3>Step-by-step explanation: </h3>

<u>Find the slope of the perpendicular line</u>

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are negative-reciprocals of each other.

⇒ if the slope of this line = 2 (y = 2x + 2)

then the slope of the perpendicular line (m) = - ¹/₂

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

⇒ y - 3 = - ¹/₂ (x - 4)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

since y - 3 = - ¹/₂ (x - 4)

y = - ¹/₂ x + 5 (in slope-intercept form)

8 0

2 years ago

Can anyone please solve this problem? Please answer, help me out

lesya [120]

I believe the answer is 62

8 0

3 years ago

Read 2 more answers

3. Solve the equation| 3x - 1| + 5 = 3​

3. Solve the equation| 3x - 1| + 5 = 3