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Elden [556K]
3 years ago
9

If a girl is 99 lb's and she eats a lb of nacho does that mean she is 1% nacho

Chemistry
2 answers:
castortr0y [4]3 years ago
6 0
Yes, probably! LOL This one got me laughing.
Julli [10]3 years ago
4 0
No. that does not mean that
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Determine the [OH−] of a solution that is 0.115 M in CO32−. For carbonic acid (H2CO3), Ka1=4.3×10−7 and Ka2=5.6×10−11.
lianna [129]

Answer:

[OH⁻] = 4.3 x 10⁻¹¹M in OH⁻ ions.

Explanation:

Assuming the source of the carbonate ion is from a Group IA carbonate salt (e.g.; Na₂CO₃), then 0.115M Na₂CO₃(aq) => 2(0.115)M Na⁺(aq) + 0.115M CO₃²⁻(aq). The 0.115M CO₃²⁻ then reacts with water to give 0.115M carbonic acid; H₂CO₃(aq) in equilibrium with H⁺(aq) and HCO₃⁻(aq) as the 1st ionization step.

Analysis:

            H₂CO₃(aq)     ⇄     H⁺(aq)    +    HCO₃⁻(aq); Ka(1) = 4.3 x 10⁻⁷

C(i)          0.115M                      0                  0

ΔC              -x                        +x                  +x

C(eq)    0.115M - x                   x                    x

            ≅ 0.115M

Ka(1) = [H⁺(aq)][HCO₃⁻(aq)]/[H₂CO₃(aq)] = [(x)(x)/(0.115)]M = [x²/0.115]M

= 4.3 x 10⁻⁷  => x = [H⁺(aq)]₁ = SqrRt(4.3 x 10⁻⁷ · 0.115)M = 2.32 x 10⁻⁴M in H⁺ ions.

In general, it is assumed that all of the hydronium ion comes from the 1st ionization step as adding 10⁻¹¹ to 10⁻⁷ would be an insignificant change in H⁺ ion concentration. Therefore, using 2.32 x 10⁻⁴M in H⁺ ion  concentration, the hydroxide ion concentration is then calculated from

[H⁺][OH⁻] = Kw => [OH⁻] = (1 x 10⁻¹⁴/2.32 x 10⁻⁴)M = 4.3 x 10⁻¹¹M in OH⁻ ions.

________________________________________________________

NOTE: The 2.32 x 10⁻⁴M  value for [H⁺] is reasonable for carbonic acid solution with pH ≅ 3.5 - 4.0.

4 0
3 years ago
Calculate the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 ml solution.
Lelechka [254]

Taking into account the definition of molarity, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liter}.

<h3>Molarity in this case</h3>

In this case, you have:

  • number of moles= 0.2 moles
  • volume= 100 mL= 0.1 L

Replacing in the definition of molarity:

molarity=\frac{0.2 mole}{0.1 L}

Solving:

<u><em>molarity= 2 </em></u>\frac{moles}{liter}

Finally, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

Learn more about molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

8 0
2 years ago
How is the energy divided up in the plant
Lerok [7]
When a crop of wheat grows, new organic matter is created by the process of photosynthesis, which converts light energy into energy stored in chemical bonds within plant tissue. ... New compounds and structures are synthesized, cells divide, and the plant grows in size over time
thanks
cbuck763
8 0
3 years ago
Read 2 more answers
Write the ground-state electron configuration for the chloride ion.You may write either the full or condensed electron configura
dalvyx [7]

Answer:

1s^22s^22p^63s^23p^6

Explanation:

Chlorine is the element of group 17 and third period. The atomic number of chlorine is 17 and the symbol of the element is Cl.

The electronic configuration of the element chlorine is:-

1s^22s^22p^63s^23p^5

Chloride ion is formed when chlorine atom gain one more electron. So, the ground-state electron configuration for the chloride ion is:-

1s^22s^22p^63s^23p^6

8 0
3 years ago
Why were they put into water before we tested them?
klasskru [66]

explain the question your asking

7 0
3 years ago
Read 2 more answers
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