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Andrei [34K]
2 years ago
13

Tonya had a mixture of sand, salt, iron particles, and pebbles. What processes should be used to separate the substances in the

mixture from each other?
Chemistry
1 answer:
marusya05 [52]2 years ago
3 0

Explanation:

Put the pan into a water-containing dish and mix well. Now use a strainer to transfer the solution into another jar. The salt should disappear in it. 

And using a tube with a filtrate, transfer the salts that has sand into another bottle with a filtrate. Therefore the sand is split. Eventually, when all the water vaporizes and the salt stays in the bottle, leave the extra solvent and heat it.

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What do nuclear reactions change in the atom?
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You need 455 ml of a 75% alcohol solution. on hand, you have a 25% alcohol mixture. you also have a 90% alcohol mixture. how muc
marishachu [46]
X ml - <span>25% alcohol mixture
y ml - </span><span>90% alcohol mixture

x+y = 455 

0.25x ml alcohol in </span>x ml of  25% alcohol mixture
0.9y ml alcohol in y ml of  90% alcohol mixture
0.75*455= 341.25 ml alcohol in 455 ml of  75% alcohol mixture

0.25x+0.9y=341.25 

System of equations:

x+y = 455 /*(-0.25) ------> -0.25x-0.25y = -0.25*455 
0.25x+0.9y=341.25

-0.25x-0.25y=-113.75
0.25x+0.9y=341.25    Add both equations

0.25x+0.9y-0.25x-0.25y=341.25-113.75
0.65y =227.5
y=227.5/0.65 = 350 ml  of  90% alcohol mixture

x+y=455
x+355=455
x=100 ml of  25% alcohol mixture

8 0
3 years ago
Find the number of molecules in 27 grams of water
Aleks04 [339]

In this question we have given the gram of water and we know that 1 mole of water = 18 gram of water and 27 g of water contain 1.5 g of water 27 / 18 = 1.5 g

As we know that avogandro'S no is equal 6.022*1023

1.5g * 6.022*1023 = 9.0 * 1023 molecules present in each 27 g of water.

I hope you will understand better now if you like then comment below and tell me. Best of luck.

5 0
3 years ago
Do you expect a strong chemical bond to have a higher or lower frequency than a weak bond?
Llana [10]

Answer:

Higher frequency  

Explanation:

We can imagine a chemical bond between two atoms as if it were two balls connected by a spring.

According to Hooke's Law, the stretching frequency f is

f = \dfrac{1}{2 \pi}\sqrt{ \dfrac {k}{\mu}}

where µ is the reduced mass of the system

\mu = \dfrac{m_{1} + m_{2}}{m_{1}m_{2} }

The strength of the bond is analogous to k, the force constant of the spring. Then,

f \propto \sqrt{k}

Thus, the stronger the bond, the greater the frequency of vibration.

6 0
3 years ago
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