All categories

3 years ago

What compound consists of 0.248 g magnesium, 0.655 g sulfur, and 1.31 g oxygen

Chemistry

1 answer:

Ivenika [448]3 years ago

3 0

Magnesium Peroxydisulphate with formula of MgS₂O₈.

<h3><u>Explanation:</u></h3>

The question clearly stands on the concept of molarity and atomic weights.

The atomic weight of magnesium = 24.

The atomic weight of sulphur = 32.

The atomic weight of oxygen = 16.

The amount of magnesium present = 0.248 g

The amount of sulphur present = 0.665 g.

The amount of oxygen present = 1.31g.

So, moles of magnesium present = 0.01 moles.

Moles of sulphur present = 0.02 moles.

Moles of oxygen present = 0.08 moles.

So, mole ratio of the compound as magnesium : sulphur : oxygen = 1:2:8.

So the compound is Magnesium Peroxydisulphate with formula of MgS₂O₈.

You might be interested in

1) If a bottle of olive oil contains 1.3 kg of olive oil, what is the volume, in milliliters, of the olive oil? Express your ans

pychu [463]

Answer:

1) 1.4 × 10³ mL

2) 0.913 kg

3) 1.1 g

Explanation:

Step 1: Calculate the volume of 1.3 kg of olive oil

The density of olive oil is 0.917 kg/L.

1.3 kg × (1 L/0.917 kg) = 1.4 L

Step 2: Convert the volume to mL

We will use the relationship 1 L = 10³ mL.

1.4 L × (10³ mL/1 L) = 1.4 × 10³ mL

Step 1: Calculate the mass of the cannon ball

The density of iron is 7.87 g/cm³.

116 cm³ × 7.87 g/cm³ = 913 g

Step 2: Convert the mass to kg

We will use the relationship 1 kg = 10³ g.

913 g × (1 kg / 10³ g) = 0.913 kg

Step 1: Calculate the mass of the helium in the balloon

The density of balloon is 0.18 g/L.

6.1 L × 0.18 g/L = 1.1 g

3 0

3 years ago

Identify which method of thermal energy transfer would be fastest through a vacuum, which would be fastest through a gas, and wh

Neporo4naja [7]

Hello!

1)Through vacuum, the fastest method of thermal energy transfer would be radiation. This kind of thermal energy transfer consists in energy carried out from a radiant body by electromagnetic waves at the speed of light e.g. the heat from the Sun. Radiation doesn't involve contact between the two bodies by any solid or fluid.

In the vacuum, the fastest way for heat to be transferred would be through radiation because the electromagnetic waves would be faster than any other heat transfer method and because there is no contact as there is no solid or fluid between the two bodies.

2) Through a gas: The fastest method of thermal energy transfer would be convection. Convection is the heat transfer by the real movement of molecules of a fluid. A gas is a fluid, and it would experience this kind of energy transfer as the molecules move.

Earth's atmosphere experience this kind of energy transfer, as large air masses move by convection, creating wind currents.

3) Through a solid: The fastest method of thermal energy transfer would be conduction. Conduction consists in the heat transfer between two bodies by molecular agitation but there is no movement involved i.e. the bodies are not fluids.

In the case of a solid, this kind of energy transfer will depend on a constant known as Thermal Conductivity, which allows assessing the ability to transfer heat through a solid.

Have a nice day!

3 0

4 years ago

Read 2 more answers

Which reaction is an example of an endothermic reaction?

Tasya [4]

Answer:

These examples could be written as chemical reactions, but are more generally considered to be endothermic or heat-absorbing processes: Melting ice cubes. Melting solid salts. ... Converting frost to water vapor (melting, boiling, and evaporation, in general, are endothermic processes.

Explanation:

8 0

4 years ago

Read 2 more answers

Calculate the standard heat of reaction for the following methane-generating reaction of methanogenic bacteria: 4CH3NH2(g) + 2H2

PIT_PIT [208]

<u>Answer:</u> The standard heat for the given reaction is -138.82 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$4CH_3NH_2(g)+2H_2O(l)\rightarrow 3CH_4(g)+CO_2(g)+4NH_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(3\times \Delta H_f_{(CH_4(g))})+(1\times \Delta H_f_{(CO_2(g))})+(4\times \Delta H_f_{(NH_3(g))})]-[(4\times \Delta H_f_{(CH_3NH_2(g))})+(2\times \Delta H_f_{(H_2O(l))})]$

We are given:

$\Delta H_f_{(H_2O(l))}=-285.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-46.1kJ/mol\\\Delta H_f_{(CH_4(g))}=-74.8kJ/mol\\\Delta H_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H_f_{(CH_3NH_2(g))}=-22.97kJ/mol$