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jolli1 [7]
4 years ago
14

The difference of a number and six is the same as five times the sum of the number and two what is the number

Mathematics
1 answer:
mezya [45]4 years ago
3 0

Answer:

x =  - 15

Step-by-step explanation:

x - 6 = 5(x + 6) \\  = x - 6 = 5x + 30(open \: the \: bracket) \\  = collect \: like \: terms \\  = x - 5x = 30 + 6 \\  =  - 4x = 36  \\ divide \: by \: the \: coefficient \: of \: x =  - 4 \\  =  - 15

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FIND VALUEE OF Y !!!
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4 years ago
The density of Venus, compared to Earth having a density of 1,
guapka [62]

Answer:

Mercury

Step-by-step explanation:

We'll translate this into ratios.

First, V:E = 0.943:1

Then, M:E = 0.983:1

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4 years ago
A 1,000 mL solution of acetic acid contains 26 mL of pure acetic acid. Find the percent concentration of this solution.
Mrac [35]

Given:

Total solution : 1000mL

Pure acetic acid = 26mL

To find:

The percent concentration of given solution.

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We know that,

\text{Percent concentration}=\dfrac{\text{Pure acetic acid}}{\text{Total solution}}\times 100

Putting the given values, we get

\text{Percent concentration}=\dfrac{26}{1000}\times 100

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6 0
3 years ago
Write the standard form of the equation of the circle with center (7,1) that also contains the point (−1,−5).
Karo-lina-s [1.5K]

Answer:

(x-7)^2+(y-1)^2=100

Step-by-step explanation:

<u>1) Find the radius</u>

We can do this by using the distance equation with the centre (7,1) and the given point (-1,-5):

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where the two points are (x_1,y_1) and (x_2,y_2)

Plug in the points (7,1) and (-1,-5)

d=\sqrt{(-1-7)^2+(-5-1)^2}\\d=\sqrt{(-8)^2+(-6)^2}\\d=\sqrt{64+36}\\d=\sqrt{100}\\d=10

Therefore, the radius of the circle is 10 units.

<u>2) Plug the data into the equation of a circle</u>

Equation of a circle (when not centred at the origin):

(x-h)^2+(y-k)^2=r^2 where the centre is (h,k) and r is the radius

Plug in the centre (7,1) as (h,k)

(x-7)^2+(y-1)^2=r^2

Plug in the radius 10

(x-7)^2+(y-1)^2=10^2\\(x-7)^2+(y-1)^2=100

I hope this helps!

4 0
3 years ago
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