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prisoha [69]
3 years ago
8

Please someone help me with this!

Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

<u>Please read the answer below.</u>

Step-by-step explanation:

<u>Question 2. 25% of what number is 30?</u>

25% - Whole 30, 50% Whole 60, 75% Whole 90, 100% Whole 120

<u>Question 3. What operation did you use the find the whole?</u>

In the previous question, I found the whole, adding 30 to the previous value.

For example, I added 30 to 30 and calculate 60. To 60 then i added 30 to get 90 and added 30 to get 120 because in this question, all the 4 parts were exactly the same size (30).

<u>Question 4. What are you multiplying/dividing? Do you use the percent or something else?</u>

In the specific case of question 2, I noticed that the size of the parts were exactly the same, using it for calculating the whole. If 1 part out of 4 is 30, then 2 parts or 50% are 60, 3 parts or 75% are 90 and then 4 parts of 100% are the whole I'm being asked, in this case, 120.

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Emilio writes the inequality 17(f+2)+45.99&lt;200 The situation using the variable as to represent the number of friends solve a
larisa [96]

Answer:

7 friends

Step-by-step explanation:

Given the inequality expression

17(g+2)+45.99<200

We are to find the value of g that satisfies the inequality

Expand

17g+34 +45.99<200

17g+79.99<200

Subtract 79.99 from both sides

17g+79.99-79.99<200-79.99

17g<120.01

g<120.01/17

g<7.059

Hence the max number of friend that can attend is 7friends.

7 0
3 years ago
If one person recruits five people and each recruited person recruits 5 more, and so on, 15 cycles; how many people would that b
jek_recluse [69]

Answer:

y=5^x

5^15= 30517578125 people

Step-by-step explanation:

x=# of cycles= 15 cycles

y= #of people recruited = what we're figuring out

Plug in 15 for x in the equation y=5^x

y= 5^15= 30517578125 people

3 0
3 years ago
PLEASE ANSWER 20 POINTS
makkiz [27]
X=58 the exterior angle is “D” 60degrees
8 0
3 years ago
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively.
Step2247 [10]
Hello,

a(2)=-6
a(3)=-6*r
a(4)=-6*r²
a(5)=-6*r^3=162
a(5)/a(2)=r^3=162/(-6)=-27==>r=-3

a(1)=-6/(-3)=2
a(2)=2*(-3)
a(3)=2*(-3)²
a(4)=2*(-3)^3
a(5)=2*(-3)^4

a(n)=2*(-3)^(n-1)




Answer
5 0
3 years ago
Read 2 more answers
HURRY PLEASE!<br> (g+2)^5
KengaRu [80]

Step-by-step explanation:

We need to use the binomial theorem/Pascal's triangle here.

(a+b)^5 = (5 choose 0)a^5 + (5 choose 1)a^4*b + (5 choose 2)a^3*b^2 + (5 choose 3)a^2*b^3 + (5 choose 4)a*b^4 + (5 choose 5)b^5.

5 choose 0 = 1

5 choose 1 = 5

5 choose 2 = 10

5 choose 3 = 10

5 choose 4 = 5

5 choose 5 = 1

And 1, 5, 10, 10, 5, 1, is the (5+1) = 6th row of pascal's triangle.

Therefore we get

g^5 + 5g^4*2 + 10g^3*2^2 + 10g^2*2^3 + 5g*2^4 + 2^5

which is

g^4 + 10g^4 + 40g^3 + 80g^2 + 80g + 32

Or, you could do the slow way, by just doing (g+2)(g+2)(g+2)(g+2)(g+2)

3 0
3 years ago
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