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prisoha [69]
3 years ago
8

Please someone help me with this!

Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

<u>Please read the answer below.</u>

Step-by-step explanation:

<u>Question 2. 25% of what number is 30?</u>

25% - Whole 30, 50% Whole 60, 75% Whole 90, 100% Whole 120

<u>Question 3. What operation did you use the find the whole?</u>

In the previous question, I found the whole, adding 30 to the previous value.

For example, I added 30 to 30 and calculate 60. To 60 then i added 30 to get 90 and added 30 to get 120 because in this question, all the 4 parts were exactly the same size (30).

<u>Question 4. What are you multiplying/dividing? Do you use the percent or something else?</u>

In the specific case of question 2, I noticed that the size of the parts were exactly the same, using it for calculating the whole. If 1 part out of 4 is 30, then 2 parts or 50% are 60, 3 parts or 75% are 90 and then 4 parts of 100% are the whole I'm being asked, in this case, 120.

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Arte-miy333 [17]

Answer:

P= A + B + C

Step-by-step explanation:

P= Side + base + Side

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4 years ago
Help me with this math question please.
solong [7]

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Step-by-step explanation:

Write the ratios of erasers to cost (dropping the dollar sign) as fractions:

(number of erasers)/(price): 2/1 and 10/4

The question is if the ratios 2/1 and 10/4 are equivalent.

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3 years ago
find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:
lbvjy [14]

Answer:

a = 4

b = -2

Step-by-step explanation:

If the given function is continuous at x = 1

\lim_{x \to 1^{-}} f(x)=(x+1)

                     =2

\lim_{x \to 1^{+}} f(x)=ax+b

                     =a+b

\lim_{x \to 1} f(x)=ax+b

                   =a+b

And for the continuity of the function at x = 1,

\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

\lim_{x \to 2^{-}} f(x)=ax+b

                     =2a+b

\lim_{x \to 2^{+}} f(x)=3x

                     =6

\lim_{x \to 2} f(x)=3x

                   =6

Therefore, \lim_{x \to 2^{-}} f(x)=\lim_{x \to 2^{+}} f(x)=\lim_{x \to 2} f(x)

2a + b = 6 -----(2)

Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

3 0
3 years ago
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