Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
Let Sara weight =x+25
amber wiegh =x
x+25+x=205
x= 90
Sara weight is 90+25= 115
Answer:
$21.10=3.10+2m.
Step-by-step explanation:
If the total fare was $21.50, then that is what it will all have to equal out to.
They charged a pick-up fee of $3.10. Which means that no matter how far you go, you will pay that. Then an extra $2 per mile. If m is mile, then it would be 2m because it is $2 per extra mile. Then add the pick-up fee of $3.10 and you will get your answer of $21.50=3.10+2m.
