Answer: 1.09 g
Explanation:
If we use the approximation that 1 mole is 22.4 L, then setting up a proportion,
- 1/22.4 = x/0.345 (x is the number of moles in the sample)
- x = 0.0154 mol
Since the mass of a mole of chlroine is about 70.9 g/mol, (0.0154)(70.9) = 1.09 g (to 3 s.f.)
It is true. The particles near the surface have enough kinetic energy to be able to escape away as gas.
<span>Ammonium ion when protonated, the result ammonium ion is not electophilic where in the case of iminium ion when protonated the result is electrophilic iminium ion that would have tendency to attract electrons. Protonate means sending a proton to the molecule to form a coordinate bond.</span>
Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Na and Cl,
E.N of Chlorine = 3.16
E.N of Sodium = 0.93
________
E.N Difference 2.23 (Ionic Bond)
For C and O,
E.N of Oxygen = 3.44
E.N of Carbon = 2.55
________
E.N Difference 0.89 (Polar Covalent Bond)
For N and Cl,
E.N of Chlorine = 3.16
E.N of Notrogen = 3.04
________
E.N Difference 0.12 (Non-Polar Covalent Bond)
For B and O,
E.N of Oxygen = 3.44
E.N of Boron = 2.04
________
E.N Difference 1.40 (Polar Covalent Bond)
Answer : The concentration of AB after 14.0 s is, 0.29 M
Explanation :
The expression used for second order kinetics is:
where,
k = rate constant =
t = time = 14.0 s
= final concentration = ?
= initial concentration = 1.50 M
Now put all the given values in the above expression, we get:
Therefore, the concentration of AB after 14.0 s is, 0.29 M