Answer:
35
Explanation:
We are given that
Initial voltage,
Final voltage, 
Number of tuns in primary coil of the transformer, 
Rms current, 

We have to find the number of turns are there on the secondary coil.
We know that

Using the formula


Hence, there are number of turns on the secondary coil=35
Answer:
450N
Explanation:
Given data
Mass m= 75kg
Acceleration= 6m/s^2
From the Newtons first law, F=ma
substitute
F=75*6
F= 450N
Hence the force is 450N
Answer:
C.) To indicate different versions of the same variable.
Explanation:
Variables in physics often include a subscript. These subscripts are used for indicating different versions of the same variable in physics.
Basically, subscripts are used to represent the beginning (initial) and ending (final) position or point of a variable in physics.
For example, we would look at Gay Lussac' Law of gases.
Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;


Where;
represents the initial temperature.
represents the initial temperature.
represents the initial pressure.
represents the initial pressure.
Note: 1 and 2 are the subscript while T and P are the variables.
Answer:
Explanation:
Given
mass of tin 
Also we know that
specific heat of tin 
Melting Point of Tin 
Heat required to raise the temperature of 100 gm tin is given by

where 



