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Murljashka [212]
3 years ago
14

Question 2 of 25

Physics
1 answer:
True [87]3 years ago
5 0

Answer: The symbol representing  the result of a  gas expanding against a constant pressure is W

Explanation:

According to first law of thermodynamics, energy can neither be destroyed nor created but rather transferred to one place to another and converted to and from other energy forms.

The mathematical form of first law of thermodynamics is:

\Delta U=q+W

where \Delta U = change in internal energy

q = heat absorbed or released

W = work  (W= P\Delta V)

P = pressure

\Delta V = volume change

Thus the changes in heat or work leads to change in internal energy.

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26. Keenan found the mass of a book to be 4.56*10^ -2 kg . What is the mass of the book in milligrams?​
vagabundo [1.1K]

Taking into account the rule of three for the change of units, the mass of the book is 45600 miligrams.

First of all, the rule of three is a mathematical tool that helps you quickly solve proportionality problems.

Having three known values ​​and one unknown, a proportional relationship is established between all of them in order to find the fourth term of the proportion.

If the relationship between the magnitudes is direct (when one magnitude increases, so does the other; or when one magnitude decreases, so does the other), the rule of three is applied as follows, where a, b and c are known values ​​and x is the unknown to calculate:

a → b

c → x

So: x=\frac{cxb}{a}

Being 1 kg equivalent to 1000000 milligrams, In this case the rule of three is applied as follows: if 1 kg equals 1000000 milligrams, 4.56×10⁻² kg equals how many milligrams?

1 kg → 1000000 milligrams

4.56×10⁻² kg  → x

So:

x=\frac{4.56x10^{-2} kg x1000000 miligrams }{1 kg}

<u><em>x=45600 miligrams</em></u>

In summary, the mass of the book is 45600 miligrams.

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7 0
3 years ago
1. An astronaut in a spacesuit has a mass of 80 kilograms. What is the weight of this astronaut on the surface of the Moon where
Andrews [41]
Weight = 80 x (9.8/6) = .... N
8 0
2 years ago
Air, considered an ideal gas, is contained in an insulated piston-cylinder assembly outfitted with a paddle wheel. It is initial
Maru [420]

Our data are,

State 1:

P_1= 10psi=68.95kPa\\V_1 = 1ft^3=0.02831m^3\\T_1 = 100\°F = 310.93K

State 2:

P_2 =5psi=34.474kPa\\V_2 = 3ft^3=0.0899m^3

We know as well that 3BTU=3.16kJ/K

To find the mass we apply the ideal gas formula, which is given by

P_1V_1=mRT_1

Re-arrange for m,

m= \frac{P_1V_1}{RT_1}\\m= \frac{68.95*0.02831}{(0.287)310.9}\\m=0.021893kg=0.04806lbm\\

Because of the pressure, temperature and volume ratio of state 1 and 2, we have to

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

Replacing,

T_2 = \frac{P_2V_2}{P_1V_1}T_1\\T_2 =\frac{34.474*0.0844}{68.95*0.02831}*310.93\\T_2 = 464.217K=375.5\°F

For conservative energy we have, (Cv = 0.718)

W = m C_v = 0.718  \Delta T +dw\\dw = W - mv\Delta T\\dw = 3.16-(0.0218*0.718)(454.127-310.93)\\dw = 0.765kJ=0.72BTU

3 0
3 years ago
The LIGHT/DARKcontrol of an automatic toaster is placed at a particular setting. The toast at this setting will always be the sa
hichkok12 [17]
The toast at this setting will always be the same color because the toaster uses a compensating thermostat. Depending on the setting, the compensating thermostat will be used to regulate the heat settings at different amounts of time. In one setting, the compensating thermostat could go on for much longer than the other setting before shutting off.
5 0
2 years ago
A horizontal compass is placed 21 cm due south from a straight vertical wire carrying a 36 a current downward. in what direction
Anit [1.1K]

 <span>
The needle of a compass will always lies along the magnetic field lines of the earth. 
A magnetic declination at a point on the earth’s surface equal to zero implies that 
the horizontal component of the earth’s magnetic field line at that specific point lies along 
the line of the north-south magnetic poles. </span>

The presence of a current-carrying wire creates an additional <span>
magnetic field that combines with the earth’s magnetic field. Since magnetic 
<span>fields are vector quantities, therefore the magnetic field of the earth and the magnetic field of the vertical wire must be combined vectorially. </span></span>

<span>
Where:</span>

B1 = magnetic field of the earth along the x-axis = 0.45 × 10 ⁻ ⁴ T

B2 = magnetic field due to the straight vertical wire along the y-axis

We can calculate for B2 using Amperes Law:

B2 = μ₀ i / [ 2 π R ]

B2 = [ 4π × 10 ⁻ ⁷ T • m / A ] ( 36 A ) / [ 2 π (0.21 m ) ] <span>
B2 = 5.97 × 10 ⁻ ⁵ T = 0.60 × 10 ⁻ ⁴ T </span>

The angle can be calculated using tan function:<span>
tan θ = y / x = B₂ / B₁ = 0.60 × 10 ⁻ ⁴ T / 0.45 × 10 ⁻ ⁴ T <span>
tan θ = 1.326</span></span>

θ = 53°

<span>
<span>The compass needle points along the direction of 53° west of north.</span></span>

8 0
3 years ago
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