Answer:
15.8 m/s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 32 m/s.
Acceleration (a) = – 1.5 m/s²
Time (t) = 10.8 s.
Final velocity (v) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = [final velocity (v) – initial velocity (u)] / time (t)
a = (v – u) /t
With the above formula, we can obtain the final velocity of go-cart driver as follow:
Initial velocity (u) = 32 m/s.
Acceleration (a) = – 1.5 m/s²
Time (t) = 10.8 s.
Final velocity (v) =?
a = (v – u) /t
– 1.5 = (v – 32) / 10.8
Cross multiply
(v – 32) = –1.5 × 10.8
v – 32 = – 16.2
Collect like terms
v = – 16.2 + 32
v = 15.8 m/s
Therefore, the final velocity of go-cart driver is 15.8 m/s.
Answer: the friction force on the small block at t equals 1 second is 2N
Explanation:
Given the data in the question;
from the slope in the graph provided, we will get the acceleration of the slab
At t = 1 seconds
Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²
Force = ma = 4 × 0.5 = 2 N
so by Newton's third law
Force on block will be same which is 2N
Therefore the friction force on the small block at t equals 1 second is 2N
Answer : to pick up safely..
Place one hand under her front legs and position your other hand so that it supports her back legs and hind quarters.
Answer:
Explanation:
m = Mass of stick
L = Length of stick = 1 m
h = Center of mass of stick = 
g = Acceleration due to gravity
T = Time period = 0.85 s
Time period is given by
Moment of inertia is given by
The acceleration of gravity on this planet is
