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Olin [163]
2 years ago
8

A 7.0 kg bowling ball has a moment of inertia of 2.8x10-2 kg m2, and a radius of 0.10 m. If it rolls down the lane at an angular

speed of 40 rad/s without slipping, determine its angular momentum.
Physics
1 answer:
slega [8]2 years ago
8 0

Hi there!

Angular momentum is equivalent to:

\large\boxed{L = I\omega}

L = angular momentum (kgm²/s)

I = moment of inertia (kgm²)

ω = angular velocity (rad/sec)

Plug in the given values for moment of inertia and angular speed:

L = (0.028)(40) = \boxed{1.12 kgm^2/s}

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Answer:

69.66 Joule

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K = \frac{1}{2}\times 8.29\times 3.6^{2}+ \frac{3}{2}\times 0.820\times 3.6^{2}

K = 69.66 J

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3 years ago
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