Answer:
Step-by-step explanation:
Let's use the definition of the Laplace transform and the identity given:
with
.
Now,
. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that
.
Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that
.
Solving for F(s) on the last equation,
, then the Laplace transform we were searching is
A data point that is insignificantly larger or smaller than other values. for example...
2 3 6 1 129, 129 is an outlier because it is insignificantly larger than the others