Answer:
435=107+82+246
Step-by-step explanation:
I think this is correct. Someone correct me if I am wrong, but I took 435 and subtracted 107, then I took that number and divided it by 4 and took one of those 4 and put it in the equation then multiplied the last three.
Answer: 12 tables minimum, 15 max.
Step-by-step explanation:
If you substitute 14 in an inequality
200c + 500t >= 8800
200(14) + 500t and solve for t, you get t must be at least 12.
C +T cannot exceed 29
So figure 14 +12 =26 so they could sell up to 15 tables and not go over 29.
You will have to enter the t values 12,13,14,15
Answer:
20
Step-by-step explanation:
Assuming that the equation is x³ = 64, that can be solved by putting cube root on both sides like so: ∛(x³) = ∛64, which simplifies to <em>x = 4</em>.
Plugging that into our expression gives us <em>4² + 4</em>, which is 20.
Answer:
no. see below
Step-by-step explanation:
This much of Josh's working is correct:
x^2-6x=7
x^2-6x+9=7+9
(x-3)^2=16
At this point Josh apparently overlooked the fact that he needed to take the square root of both sides of the equation. Had he done that, he would have ...
x -3 = ±4
x = 3+4 . . . or . . . 3 -4
x = 7 or -1
_____
Josh reported values of x that would match ...
x -3 = ±16
He <em>violated the equal sign</em> by taking the square root on the left, and multiplying by ±1 on the right. Doing different operations on the two sides of the equation will mean the value of x is changed to something other than what you're looking for.
