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3 years ago

Whats the equation for this please help

Mathematics

2 answers:

kykrilka [37]3 years ago

8 0

$y = \frac{1}{3} {x}^{2} - 3$

Step-by-step explanation:

The general vertex form of the equation is

$y = a {(x - h)}^{2} + k$

where (h, k) are the coordinates of the vertex and a is a constant. In your case, the vertex is located at (0, -3) so your equation becomes

$y = a {x}^{2} - 3$

To find a, substitute the point (3, 0) into the equation

0 = a(3)^2 - 3 ---> a = 1/3

Therefore, the equation has the form

$y = \frac{1}{3} {x}^{2} - 3$

Gnoma [55]3 years ago

5 0

Answer:

y = ⅓ x² - 3

Step-by-step explanation:

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3 years ago

If f'(0) = 5 and F(x) = f(3x), what is F'(0)?

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Step-by-step explanation:

We are given that:

$f'(0) = 5 \text{ and } F(x) = f(3x)$

And we want to find F'(0).

First, find F(x):

$\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]$

From the chain rule:

$\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}$

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2 years ago

Read 2 more answers

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