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3 years ago

You need to add cells c3 and c7, and multiply c3 by c6. based on the order of operations, what would you do

Computers and Technology

2 answers:

Julli [10]3 years ago

6 0

Multiply first, and then add.

serg [7]3 years ago

3 0

Answer:

First multiplication and then addition

Explanation:

The order of operations establish the next sequence of operations:

first, simplify inside of parentheses

then, compute exponentials

after that, compute multiplications and divisions

and finally, compute additions and subtractions.

Based on this, multiplication between C3 and C6 goes first and then goes addition between C3 and C7.

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Please debug the below code in Java please.

lisabon 2012 [21]

Answer:

Check the explanation

Explanation:

//Bugs are highlighted in bold text

class Invoice

Declarations

private num invoiceNumber

private string customer

private num balanceDue

private num tax

public void setInvoiceNUMBER(num number)

Declarations

num LOW_NUM = 1000

num HIGH_NUM = 9999

if number > HIGH_NUM then

invoiceNumber = 0

else

if number < LOW_NUM then

invoiceNumber = 0

else

invoiceNumber = num

endif

return

public void setCustomer(string cust)

customer = cust

return

public void setBalanceDue(num balance)

//Bug balanceDue is Invoice class varible

//but it is assigned to balance .it gives error

balance = balanceDue

setTax()

return

private void setTax()

Declarations

//Bug TAX_RATE is declared as string

//but assigned a double value

string TAX_RATE = 0.07

tax = tax * TAX_RATE

return

public void displayInvoice()

output "Invoice #", invoiceNumber

output "Customer: ", customer

output "Due: ", balanceDue

output "Tax: ", taxDue

//Bug

//Invoice class has no variable called balance .it should be balanceDue

output "Total ", balance + taxDue

return

endClass

start

Declarations

Invoice inv1

Invoice inv2

Invoice inv3

//Warning

//it gives warning object taken but not initilaized

Invoice inv4

inv1.setInvoiceNumber(1244)

inv1.setCustomer("Brown")

inv1.setBalanceDue(1000.00)

inv1.displayInvoice()

inv2.setInvoiceNumber(77777)

inv2.setCustomer("Jenkins")

inv2.setBalanceDue(2000.00)

inv2.displayInvoice()

inv3.setInvoiceNumber(888)

inv3.setCustomer("Russell")

inv3.setBalanceDue(3000.00)

//Bug

//setTax method of Invioce doesnot take any arguments

inv3.setTax(210.00)

inv3.displayInvoice()

stop

//Here is the complete program in c++

//Run the program using Microsoft visual studio 2010 vc++

#include<iostream>

#include<iomanip>

#include<string>

using namespace std;

class Invoice

{

//class varibales

private:

int invoiceNumber;

string customer;

double balanceDue;

double tax;

//class methods

public:

void setCustomer(string cus);

void displayInvoice();

void setBalanceDue(double balance);

void setInvoiceNUMBER(int number);

void setTax();

};

void Invoice::displayInvoice()

{

cout<< setw(10)<<"Invoice #"<<setw(5)<<invoiceNumber<<endl;

cout<<setw(10)<<"Customer: "<<setw(5)<<customer<<endl;

cout<<setw(10)<<"Due: "<<setw(5)<<balanceDue<<endl;

cout<<setw(10)<<"Tax: "<<setw(5)<<tax<<endl;

//Bug

//Invoice class has no variable called balance .it should be balanceDue

cout<< "Total "<< balanceDue + tax<<endl;

}

void Invoice::setCustomer(string cust)

{

customer = cust;

}

void Invoice::setInvoiceNUMBER(int number)

{

const int LOW_NUM = 1000;

const int HIGH_NUM = 9999;

if( number > HIGH_NUM )

invoiceNumber = 0;

else

if (number < LOW_NUM )

invoiceNumber = 0;

else

invoiceNumber = number;

}

void Invoice::setBalanceDue(double balance)

{

balanceDue = balance;

}

void Invoice::setTax()

{

double TAX_RATE = 0.07;

tax = balanceDue * TAX_RATE;

}

int main()

{

Invoice inv1;

Invoice inv2;

Invoice inv3;

inv1.setInvoiceNUMBER(1244);

inv1.setCustomer("Brown");

inv1.setBalanceDue(1000.00);

inv1.setTax();

inv1.displayInvoice();

inv2.setInvoiceNUMBER(77777);

inv2.setCustomer("Jenkins");

inv2.setBalanceDue(2000.00);

inv2.setTax();

inv2.displayInvoice();

inv3.setInvoiceNUMBER(888);

inv3.setCustomer("Russell");

inv3.setBalanceDue(3000.00);

inv3.setTax();

inv3.displayInvoice();

system("pause");

return 0;

}

Kindly check the output image below.

5 0

3 years ago

Lin is creating a template for the configuration of Windows servers in her organization. The configuration includes the basic se

larisa86 [58]

The type of document should she create is baseline document. Check more about the term Baseline below.

<h3>What is a Baseline document?</h3>

A Baseline document is known to be a kind official or legalized document that has passed through some measures of start approval and was used for its purpose.

Note that for Lin to be able to make the template for the configuration of Windows servers, the type of document that she can create is baseline document.

Learn more about Windows servers from

brainly.com/question/14526761

#SJ1

3 0

2 years ago

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less

nataly862011 [7]

Complete Question:

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with a newline. Ex: For the user input 123, 395, 25, the expected output is:

Enter a number (<100):

Your number < 100 is: 25

Answer:

import java.util.Scanner;

public class num8 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

int n;

do{

System.out.println("Enter a number (<100):");

n= in.nextInt();

}while(n>100);

System.out.println("Your number < 100 is: "+n);

}

Explanation:

Using Java programming language

Import the scanner class to receive user input

create an int variable (n) to hold the entered value

create a do while loop that continuously prompts the user to enter a number less than 100

the condition is while(n>100) It should continue the loop (prompting the user) until a number less than 100 is entered.

4 0

3 years ago

Read 2 more answers

A. Assume a computer has a physical memory organized into 64-bit words. Give the word address and offset within the word for eac

Galina-37 [17]

Answer:

Check the explanation

Explanation:

For 9th byte , it is from 8*8 bit to 9"8th bit so each word consists of 64 bits , to find word address u have to divide 8*8 by 64.

Offset within word = 9*8modulo 64.

For 27th byte , word address = 8*27/64.

Offset within word = 27* 8 modulo 64

For 21th byte , word address = 8*31/64

Offset within the word = 31*8 modulo 64

For 120 , word address = 8*120/64

Offset within the word = 120*8 modulo 64.

7 0

3 years ago

What should you do if you do not have the experience required for the job you want?

Alla [95]

Answer:

try to get an internship and learn more and gain experience and you can resign and apply for the job you want

Explanation:

hope this helps

please like and Mark as brainliest

4 0

3 years ago