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9966 [12]
3 years ago
9

A gas can holds 2.9 gal of gasoline. what is the quantity in cubic centimeters

Chemistry
1 answer:
mash [69]3 years ago
3 0
1 gal ---------- 3785.41 cm³
2.9 gal --------- ??

2.9 x 3785.41 / 1 => 10977.689 cm³
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If 54 g of Al reacted with 160 g of O2, find out the weight of product​
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Answer:

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3 years ago
I have science and i have a question that says : an element is a (valuable, pure , rare) substance that is not chemically combin
mote1985 [20]

Answer:

It’s true ( pure).

Explanation:

An element is defined as a pure substance that is not chemically combined with any other elements. An element comprises of mainly the sane type of atoms.

While a compound is a substance that consists of two or more elements which are chemically combined together. This is the main difference between an element and a compound.

3 0
3 years ago
Cell notation will list each half-reaction:
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on each side of the salt bridge, which is represented by a double vertical line

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6 0
3 years ago
answer the following: a. Explain how a pulley changes the amount of force needed to lift an object. b. do all pulleys change the
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3 years ago
Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0
3 years ago
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