Question

Consider the formation of nitryl fluoride: 2NO2(g)+F2(g)⇌2NO2F(g) The reaction is first order in F2 and second order overall. What is the rate law? View Available Hint(s) Consider the formation of nitryl fluoride: The reaction is first order in and second order overall. What is the rate law? rate=k[NO2]2[F2]2 rate=k[NO2][F2]2 rate=k[F2] rate=k[NO2] rate=k[NO2][F2] rate=k[NO2]2[F2]

Answer 1

Answer:

Rate = $k[NO_{2}][F_{2}]$

Explanation:

• Two reactants are present in this reaction which are $NO_{2}and F_{2}$
• We know overall order of a reaction is summation of individual order with respect to reactants present in rate law equation.
• Here, overall order of reaction is 2 including first order with respect to $F_{2}$
• So, rate of reaction should also be first order with respect to another reactant i.e. first order with respect to $NO_{2}$
• So, rate law: rate = $k[NO_{2}][F_{2}]$