Question

A piston contains 0.39L of air at 1.0 atm. If the pressure on the piston is increased to 5.6 atm, what is the new volume?

Answer 1

The new volume : 0.07 L

Further explanation

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

$\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

P₁=1 atm

V₁=0.39 L

P₂=5.6 atm

$\tt V_2=\dfrac{P_1.V_1}{P_2}\\\\V_2=\dfrac{1\times 0.39}{5.6}\\\\v_2=\boxed{\bold{0.07~L}}$