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MAVERICK [17]
3 years ago
9

A piston contains 0.39L of air at 1.0 atm. If the pressure on the piston is increased to 5.6 atm, what is the new volume?

Chemistry
1 answer:
bazaltina [42]3 years ago
3 0

The new volume : 0.07 L

<h3>Further explanation</h3>

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

P₁=1 atm

V₁=0.39 L

P₂=5.6 atm

\tt V_2=\dfrac{P_1.V_1}{P_2}\\\\V_2=\dfrac{1\times 0.39}{5.6}\\\\v_2=\boxed{\bold{0.07~L}}

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\boxed{\text{pH = 5.00}}

Explanation:

Step 1. Calculate the pOH

pOH =-log[OH⁻]

pOH =-log(1.0 × 10⁻⁹)

pOH = 9.00

Step 2. Calculate the pH

pH + pOH = 14.00

pH + 9.00 = 14.00

\boxed{\textbf{pH = 5.00}}

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that's the answer

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If 45.8 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced? 2KClO3 → 2KCl + 3O2
natta225 [31]
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<span>2KClO3 --> 2KCl + 3O2 </span>

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<span>Hope this helps :)</span>
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3 years ago
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4 0
4 years ago
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Explanation:

The quantity of heat energy (Q) released from a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

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