PLS HELP ASAP if you could explain how to do this as well im really slow when it comes to math :/

Abbeys cat weighs 18 pounds. Her dog weighs 2 pounds more than half her cats weight. Write and evaluate an expression to show ho

SIZIF [17.4K]

$(18 \div 2) + 2 = x$
X= lbs Abbys dog weighs
so you would take 18 divide by 2 which is 9, then you add 2. So Abbys dog weighs, 11 lbs.

4 0

3 years ago

Rafael can type 24 words in 6 minutes. What is his rate in words per minute

Xelga [282]

Answer:

24/6= 4

4 words per minute

Step-by-step explanation:

5 0

3 years ago

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Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to

attashe74 [19]

Answer:

0.9726 = 97.26% approximate probability that X is at most 30

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped).

This means that $p = 0.11$

Random sample of 200 shafts

This means that $n = 200$

Mean and Standard deviation:

$\mu = E(x) = np = 200*0.11 = 22$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.11*0.89} = 4.42$

(a) What is the (approximate) probability that X is at most 30

Using continuity correction, this is $P(X \leq 30 + 0.5) = P(X \leq 30.5)$ , which is the pvalue of Z when X = 30.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30.5 - 22}{4.42}$

$Z = 1.92$

$Z = 1.92$ has a pvalue of 0.9726.

0.9726 = 97.26% approximate probability that X is at most 30

8 0

3 years ago

Angles 1 and 2 or complementary. If <1 measures 29.6°, then what is the measure of <2?

Sever21 [200]

Complementary angles add up to 90 degrees so if one is 29.6 degrees you subtract 29.6 from 90 so the answer is 60.4 degrees.

8 0

3 years ago

The expression 87000(1.12)^t represents the population of a town t hears after 1996. By what percent does the population increas

Tamiku [17]

Answer:

12%

Step-by-step explanation:

Percentage increase of something is often represented in a formula of a format like this:

X=Ar^t

Where X represents the total amount after t years.

A or 87000 in this case represents the starting value, which is this case is the starting population of the town. r or 1.12 represents the percentage increase, if it increases by 12% than the next year has 1.12 times as many people as the previous year so this is represented by 1.12 rather than say 0.12 which would indicate a 88% decrease instead. t is the time, no. of years in this case, that has elapsed since 1996.

This formula basically means that a town population of 87000 increases by 12% for every year of time that elapses.

Hope this helped!

7 0

3 years ago

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