Question

After landing, a jetliner on a straight runway taxis to a stop at an average velocity of If the plane takes 7.00 s to come to rest, what are the plane’s initial velocity and acceleration?

Answer 1

Answer:

Plane's initial speed: 14$\frac{m}{s}$

Plane's acceleration: -1 $\frac{m}{s^{2} }$

Explanation:

average velocity =$\frac{V_{0} +V_f }{2}$

V0=?

Vf= 0 m/s (rest)

t=7 s

Isolating V0

V0=2a-Vf = 2*(7) - 0= 14$\frac{m}{s}$

Otherwise;

$a= \frac{V_f-V_0}{t} = \frac{0\frac{m}{s}-7\frac{m}{s} }{7s} = -1 \frac{m}{s^2}$