Which is the best description of our solar system's current location in the milky way?

59. (II) The crate shown in Fig. 4-60 lies on a plane tilted at an angle A = 25.0° to the horizontal, with Mk 0.19. (a) Determin

Daniel [21]

Explanation:

a) We need to write down first Newton's 2nd law as applied to the given system. The equations of motion for the x- and y-axes can be written as follows:

$x:\;\;\;\;\;mg\sin 25° - \mu_kN = ma\;\;\;\;\;\;(1)$

$y:\;\;\;\;\;N - mg\cos 25° = 0\;\;\;\;\;\;\;\;\;(2)$

From Eqn(2), we see that

$N = mg\cos 25°\;\;\;\;\;\;\;(3)$

so using Eqn(3) on Eqn(1), we get

$mg\sin 25° - \mu_kmg\cos 25° = ma$

Solving for the acceleration, we see that

$a = g(\sin 25° - \mu_k\cos 25°)$

$\;\;\;\;= 2.45\:\text{m/s}^2$

b) Now that we have the acceleration, we can now solve for the velocity of the crate at the bottom of the plane. Using the equation

$v^2 = v_0^2 + 2ax$

Since the crate started from rest, $v_0 = 0.$ Thus our equation reduces to

$v^2 = 2ax \Rightarrow v = \sqrt{2ax}$

$v = \sqrt{2(2.45\:\text{m/s}^2)(8.15\:\text{m})}$

$\;\;\;\;= 6.32\:\text{m/s}$

6 0

3 years ago

There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches 10 cm. Spring C stretches 100 cm

saul85 [17]

Answer:

spring D stretches the weakest

6 0

2 years ago

The hypotenuse of a right triangle is 29.0 centimeters. The length of one of its legs is 20.0 centimeters. What is the length of

SVEN [57.7K]

C2 = a2 + b2
29^2 = a^2 + 20^2
841 = a^2 + 400
441 = a^2
a = 21

3 0

3 years ago

Read 2 more answers

Sirius A is 8.6 light-years from Earth. What is this distance in kilometers? What is this distance in feet?

Jlenok [28]

Answer:

a. 8.136 × 10¹³ km b. 2.669 × 10¹⁹ feet

Explanation:

a. What is this distance in kilometers?

Since Sirius A is 8.6 light years away from Earth and one light year = distance travelled by light in a year = 3 × 10⁸ m/ s × 365 days/year × 24 hr/day × 3600 s/hr = 9.4608 × 10¹⁵ m = 9.4608 × 10¹² km.

Then 8.6 light years = 8.6 × 1 light year

= 8.6 × 9.4608 × 10¹² km

= 81.363 × 10¹² km

= 8.1363 × 10¹³ km

≅ 8.136 × 10¹³ km

b. What is this distance in feet?

Since 1 meter = 3.28 feet,

8.6 light years = 8.1363 × 10¹² km

= 8136.3 × 10¹⁵ m

= 8136.3 × 10¹⁵ × 1 m

= 8136.3 × 10¹⁵ × 3.28 feet

= 26687.1 × 10¹⁵ feet

= 2.66871 × 10¹⁹ feet

≅ 2.669 × 10¹⁹ feet

3 0

3 years ago

16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radi

ArbitrLikvidat [17]

The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

<h3>What does Orbital speed depend on ?</h3>

The speed of an object travelling around a circle depends on two quantities namely;

Its angular velocity w

Its distance from the center of the circle.

Given that an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

The mass of Saturn = 5.68 x 10^26 kg

The orbital radius = 3.00 x 105 km

G = 6.67 × 10-11 N·m2/kg2

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × $10^{-11}$ × 5.68 × $10^{26}$ ) ÷ (300000 × 1000)²

g = 3.79 × $10^{16}$ ÷ 9 × $10^{16}$

g = 0.421 m/s²

The orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

Learn more about Orbital Speed here: brainly.com/question/22247460

#SPJ1

4 0

1 year ago