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Phantasy [73]
3 years ago
9

Is there ever a situation where an ant will have more momentum than an elephant? Explain why or why not?

Physics
1 answer:
Mariulka [41]3 years ago
6 0

Answer:

Yes

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is the velocity of the object

We know that an elephant has a mass much larger than the mass of an ant. However, we see that the momentum of the animal also depends on its velocity.

If the elephant is at rest, its velocity is zero:

v = 0

so its momentum is also zero:

p = 0

And therefore, an ant which is moving (so, non-zero speed) can have more momentum than an elephant, if the elephant is at rest.

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Every day a certain amount of water evaporates from Earth’s oceans, lakes, and land surface and forms water vapor and clouds in
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0.0000000010 joules

Explanation:

Amount : 1540.3 nanojoules (nJ)

Equals : 0.0 joules (J)

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The image shows positivle and negative charged particles bouncing around. Which state of matter is most likely represented in th
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Gas Solid Liquid Plasma

Explanation:

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You charge a capacitor and then discharges it through a resistor. You notice that, after four time constants, the voltage across
ollegr [7]

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Explanation:

5 0
3 years ago
A catapult used by medieval armies hurls a stone of mass 32.0 kg with a velocity of 50.0 m/s at a 30.0 degree angle above the ho
NISA [10]

Answer:

The horizontal distance traveled when the stone returns to its original height = 220.81 m

Explanation:

Considering vertical motion of catapult:-

At maximum height,

Initial velocity, u =  50 sin30 = 25 m/s

Acceleration , a = -9.81 m/s²

Final velocity, v = 0 m/s

We have equation of motion v = u + at

Substituting

    v = u + at

    0 = 25  - 9.81 x t

    t = 2.55 s

Time of flight = 2 x Time to reach maximum height = 2 x 2.55 = 3.1 s

Considering horizontal motion of catapult:-

Initial velocity, u =  50 cos30 = 43.30 m/s

Acceleration , a = 0 m/s²

Time, t = 5.10 s

We have equation of motion s= ut + 0.5 at²

Substituting

   s= ut + 0.5 at²

   s = 43.30 x 5.10 + 0.5 x 0 x 5.10²

  s = 220.81 m

The horizontal distance traveled when the stone returns to its original height = 220.81 m

5 0
3 years ago
If 3.61 m3 of a gas initially at STP is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘C. What
Pavel [41]

Answer: 1.54m^3

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 1 atm

P_2 = final pressure of gas = 2.67 atm

V_1 = initial volume of gas = 3.61m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas at STP = 0^oC=273+0=273K

T_2 = final temperature of gas = 37.9^oC=273+37.9=310.9K

Now put all the given values in the above equation, we get:

\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}

V_2=1.54m^3

Thus the final volume will be 1.54m^3

7 0
3 years ago
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