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3 years ago

7. What causes waves to bend?

Physics

2 answers:

prohojiy [21]3 years ago

8 0

Answer:

Refraction

Explanation:

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lesantik [10]3 years ago

7 0

Answer:

Refraction

Explanation:

Refraction is the change in direction of waves that occurs when waves travel from one medium to another. Refraction is always accompanied by a wavelength and speed change. Diffraction is the bending of waves around obstacles and openings.

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Three students are mixing the same type of solute in 500 ml of water. Jessica is heating her solution, Larry left his on the cou

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Hunter, jessica, larry

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3 years ago

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Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above

Virty [35]

$8.98×10^6\:\text{m}$

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

$y = -\frac{1}{2}gt^2$

Solving for g, we get

$g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2$

Recall that the acceleration due to gravity on a planet's surface can be written as

$g = G\dfrac{M_p}{R_p^2}$

We can express the mass of the planet $M_p$ in terms of its density $\rho$ as follows:

$M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3$

The expression for g then becomes

$g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p$

Solving for $R_p,$ we get

$R_p = \dfrac{3g}{4\pi G\rho}$

$\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]$

$\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}$

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3 years ago

Describe one piece of evidence to show light waves do not need a medium travel from one place to another

Art [367]

Answer:

I don't know I'm sorry I will tell you another answer asks me

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3 years ago

The moon Phobos orbits Mars

Soloha48 [4]

Answer:

Explanation:

We are basically needing to solve for the time in the equation d = rt, where d is the distance around Mars (aka the circumference), r is the velocity, and t is time. We need to find the circumference and the velocity. We will begin with the velocity.

Because the gravitational attraction between Phobos and Mars provides the centripetal acceleration necessary to keep Phobos in its (sort of) circular path, the equation we use for this is:

$F_g=F_c$ which says that Force supplied by gravity is equal to the centripetal force. Expanding that: