Conservation of momentum: total momentum before = total momentum after
Momentum = mass x velocity
So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32
Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32
Therefore β = 12.8 m/s
Answer:
22) 5.6 Kg.m/s
23) 0.067 Kg
24) 1.16 m/s
Explanation:
Momentum is found by multiplying mass and velocity
P=mv where P is momentum, m is mass of object and v is the velocity
22
Given
Mass, m=2 Kg
Rate, v=2.8 m/s
Relationship
P=mv
Solution
P=mv=2*2.8=5.6 Kg.m/s
23
Given
Momentum, p=0.1 Kg.m/s
Rate, v=1.5 m/s
Relationship
P=mv and making m the subject then
Solution
24
Given
Momentum,
Mass,
Relationship
P=mv and making v the subject then
Solution
if A is closer to the x-axis then its "faster"
Metal is conductive, so electrons will transfer onto sphere b until there is an equal number of electrons on either sphere (the electrical gradient will be zero). This means that 5 x 10^11 electrons will be on either sphere, and since the charge of an electron is 1.602 x 10^-19 Coulombs, multiplying this by the number of electrons gives a charge of 8.01 x 10^-8 Coulombs, or 80.1 nanocoulombs.