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Dvinal [7]
3 years ago
7

A car crashes into a wall with an impulse of 40,000 kg.m/s. The collision took 2 seconds. How much force did the wall exert?

Physics
1 answer:
sesenic [268]3 years ago
5 0

Answer:

i hate physics lol but its 20,000N

Explanation:

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A ford escort needs a force of 3500N to accelerate at the rate of 4.9 m/s2. What is the mass of the car?
Verizon [17]

Answer:

714 kg

Explanation:

ΣF = ma

3500N = 4.9m/s^2*m

m ~= 714 kg

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How long does it take a car traveling at 45km/h to travel 100 m
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Explanation:

45 \frac{km}{hr}  \times  \frac{1000m}{1km}  = 45000 \frac{m}{hr}  \\  \frac{100m}{45000 \frac{m}{hr} }  =  \frac{1}{450} hr \\  \frac{1}{450} hr \times  \frac{60mins}{1hr}  =  \frac{2}{15} mins = 0.133mins

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3 years ago
What are the answers for each question to type in?
marin [14]
<h3>#1</h3>

  • <em>This</em><em> </em><em>is</em><em> </em><em>happening</em><em> </em><em>because</em><em> </em><em>the</em><em> </em><em>force</em><em> </em><em>exerted</em><em> </em><em>by</em><em> </em><em>both</em><em> </em><em>of</em><em> </em><em>them</em><em> </em><em>is</em><em> </em><em>equal</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>making</em><em> </em><em>the</em><em> </em><em>net</em><em> </em><em>force</em><em> </em><em>0</em><em>.</em><em> </em><em>And</em><em> </em><em>we</em><em> </em><em>know</em><em> </em><em>that</em><em> </em><em>when</em><em> </em><em>net</em><em> </em><em>force</em><em> </em><em>is</em><em> </em><em>0</em><em>,</em><em> </em><em>no</em><em> </em><em>movement</em><em> </em><em>takes</em><em> </em><em>places</em><em>.</em><em>.</em><em>.</em>

<h3>#2</h3>

For this let us take the force applied by karina 5 Newton and the force applied by Layla be 5 Newton...

Here, The forces are equal..

\sf \: 5 = 5 \\  \tt \: they \: will \: be \: cancelled \\  \sf \:  = 0

<h3>#3</h3>

  • <em>Well</em><em>,</em><em> </em><em>this</em><em> </em><em>is</em><em> </em><em>happening</em><em> </em><em>because</em><em> </em><em>now</em><em> </em><em>the</em><em> </em><em>force</em><em> </em><em>on</em><em> </em><em>karina's</em><em> </em><em>side</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>the</em><em> </em><em>force</em><em> </em><em>on</em><em> </em><em>layl</em><em>a's</em><em> </em><em>side</em><em> </em><em>making</em><em> </em><em>layla</em><em> </em><em>move</em><em> </em><em>forward</em><em> </em><em>and</em><em> </em><em>backward</em><em>.</em><em>.</em><em>.</em>

<h3>#4</h3>

Let us now the force<em> </em>applied<em> </em>by karina is 5 Newton, Force by stephanie is 5 Newton and Force by layla is 5 Newton..

\sf \: 5 = 5 + 5 \\  \sf \: 5  \not= 10 \\  \sf \: 5 < 10

5 0
1 year ago
A spinning neutron star that appears to give off radio wave pulses is called a _____.
Agata [3.3K]

Answer:

Pulsar

Explanation:

A pulsar, a pulsating star, is formed when a massive star reaches its end stage. At this stage, the core of the star is compressed and collapses into a Neutron star. It retains most of its angular momentum but a tiny fraction of its progenitor's radius. Beam of Electromagnetic radiations are emitted along the magnetic axis of the the Pulsar. When this beam is pointed towards the Earth, it appears like a pulsating star (just like a lighthouse is seen only when observes is in line of the beam of light) thus they are names as Pulsar.

3 0
3 years ago
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The speed of sound v in gas might plausibly depend on the pressure p, and the volume V of the gas. Use dimensional analysis to d
gregori [183]

Answer:

V= C√p/s

Explanation:

We are given that

Dimension of speed of sound

V = L T ^-1

Volume of gas = L³

Pressure P= M¹L^-1T^-2

Density =M¹L^-3

So

LT^-1 = C [M¹L^-1T^-2]^x [M¹L^-3]^y [L³]^z

Compare powers

We have

x+y=0

-x+3y+3z=1

-2x=-1

So x= 1/2 y= -1/2 z= 0

So finally we substitute in

V=cp^xp^y V^z

We have

V= C√p/s

4 0
3 years ago
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