Question

An empty 3.00 l bottle weighs 1.70 kg. filled with a certain wine, it weighs 4.72 kg. the wine contains 11.5% ethyl alcohol, c2h6o, by mass. how many grams of ethyl alcohol are there in 250.0 ml of this wine?

Answer 1

28.94 g of alcohol. First, calculate the mass of 3.00 l of wine. 4.72 kg = 1.70 kg = 3.02 kg Now calculate the mass of 250.0 ml of the wine. Using ratios will work for this (3020 g)/(3000 ml) = (X g)/(250 ml) Multiply both sides by 250 ml (3020 g * 250 ml) / (3000 ml) = X (755000 ml g) / (3000 ml) = X 251.667 g = X So 250.0 ml of wine has a mass of 251.667 g Now multiply by 0.115 to get the mass of alcohol 251.667 g * 0.115 = 28.94 g