The volume of the gas will be 1 L at a height of 6.5 km.
Since temperature is constant, we can use <em>Boyle’s Law</em>.
<em>p</em>₁<em>V</em>₁ = <em>p</em>₂V₂
p<em>₂</em> = <em>p</em>₁ × <em>V</em>₁/<em>V</em>₂ = 500 mL × (1 atm/0.5 atm) = 1000 mL = 1 L
2.5gm answer ....2/18x22.5
B )teeth tearing off a bite of a taco
Answer : The concentration of NaOH is, 0.336 M
Explanation:
To calculate the concentration of base, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:


Thus, the concentration of NaOH is, 0.336 M