. 9 triangles per 6 circles Triangles Circles 9 | 24 8 30 | 50 atio.

What is the antiderivative of 3x/((x-1)^2)

ValentinkaMS [17]

Answer:

3 ln(x − 1) − 3/(x − 1) + C

Step-by-step explanation:

∫ 3x / (x − 1)² dx

3 ∫ x / (x − 1)² dx

If u = x − 1, then x = u + 1, and du = dx.

3 ∫ (u + 1) / u² du

3 ∫ (1/u + 1/u²) du

3 (ln u − 1/u + C)

3 ln u − 3/u + C

Substitute back:

3 ln(x − 1) − 3/(x − 1) + C

6 0

3 years ago

Is the formula s=(n-2)180

Phantasy [73]

Answer:

Number of sides of the polygon

Step-by-step explanation:

The formula $S=(n-2)180$ is the sum of the measures of interior angles. So that's what S stands for. The only other variable remaining is n which is the number of sides of the polygon.

There's nothing I can do to help you understand this, you just have to memorize it.

5 0

3 years ago

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball traveled 79 met

Sav [38]

Answer:

0.395 kilometre

Step-by-step explanation:

Given:

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.

On his second stroke, the ball traveled 79 meters and went into the hole.

Question asked:

How many kilometres from the hole was Martin when he started?

Solution:

Let distance from Martin starting point to the hole in meters = $x$

On Martin's first stroke, ball traveled = $\frac{4}{5} \ of \ total \ distance\ to\ the\ hole$

$=\frac{4}{5} \times x=\frac{4x}{5}$

On his second stroke, the ball traveled and went to the hole = 79 meters

Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

$x=\frac{4x}{5} +79\\ \\ Subtracting\ both\ sides\ by \ \frac{4x}{5}\\ \\ x- \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5}+79\\ \\ \frac{5x-4x}{5} =79\\ \\ By \ cross\ multiplication\\ \\ x=79\times5\\ \\ x=395\ meters$