Question

Look at this linear equation. 3x + 5y = 30 Which of the following equations can be used to solve for y in the linear equation above? y = - x + 30 y = 3x + 6 y = - x + 6 y = x + 30

Answer 1

Answer:

$y=-\frac{3}{5}x+6$

Step-by-step explanation:

The given linear equation is

$3x+5y=30$

We need to solve the above equation for y.

Using subtraction property of equality, subtract 3x from both sides.

$3x+5y-3x=30-3x$

$5y=30-3x$

Using division property of equality, divide both sides by 5.

$y=\frac{30-3x}{5}$

$y=\frac{30}{5}-\frac{3x}{5}$

$y=6-\frac{3}{5}x$

Arrange the terms.

$y=-\frac{3}{5}x+6$

Therefore, the required equation is $y=-\frac{3}{5}x+6$.

Answer 2

Y=-
$\frac{3}{5} x + 6$