Subtract − 9 x − 7 −9x−7 from 8 x 2 − 5 x + 9 8x 2 −5x+9

What is the 11th term in the sequence with the nth term :

kifflom [539]

$2(11^2)+3*11-2=2*121+33-2=273$

5 0

2 years ago

25 points pluss brainliest!!! math.

BARSIC [14]

Answer: 9.97

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Explanation:

y = distance from the base of the pole to the closest person

y+200 = total horizontal distance

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Focus on the smaller right triangle.

tan(angle) = opposite/adjacent

tan(26) = 55/y

y*tan(26) = 55

y = 55/tan(26)

y = 112.76671 approximately

Make sure your calculator is in degree mode.

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Now move to the larger right triangle

tan(angle) = opposite/adjacent

tan(x) = 55/(y+200)

tan(x) = 55/(112.76671+200)

tan(x) = 55/312.76671

tan(x) = 0.17585

x = arctan(0.17585) same as $\tan^{-1}$

x = 9.97349

x = 9.97 degrees approximately

7 0

1 year ago

2 angles are supplementary. The measure of one angle is one-third of the other. Find the measure of BOTH angles.

morpeh [17]

Answer:

45° and 135°

Step-by-step explanation:

let one angle be "x" and the other be "y"

Angles which are supplementary total to 180°. This can be represented with the equation:

x + y = 180

If angle "x" is a third of angle "y", the situation is represented with this equation:

(1/3)x = y

Since fractions are difficult to work with, multiply the whole equation by 3.

(1/3)x = y <= X 3

x = 3y

Use the equations x+y=180 and x=3y.

You can substitute x=3y into x+y=180.

x + y = 180

(3y) + y = 180 <=combine like terms

4y = 180 <=isolate y by dividing both sides by 4

y = 45

Substitute y=45 itno the equation x+y=180 to find x.

x + y = 180

x + 45 = 180 <=isolate x by subtracting 45 from both sides

x = 135

Therefore the angles are 45° and 135°.

5 0

2 years ago

Read 2 more answers

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

(3x-5)/(x-5)>=0 <br> How do I get the answers for this problem?

Diano4ka-milaya [45]

$\frac{3x-5}{x-5}$ > 0

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: $\frac{3x-5}{x-5}$ = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = $\frac{5}{3}$
Sixth, from the values of x above, we have these 3 intervals to test:
x < $\frac{5}{3}$
$\frac{5}{3}$ < x < 5
x > 5
Seventh, pick a test point for each interval.

1. For the interval x < $\frac{5}{3}$ :
Let's pick x - 0. Then, $\frac{3x0-5}{0-5}$ > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval $\frac{5}{3}$ < x < 5:
Let's pick x = 2. Then, $\frac{3x2-5}{2-5}$ > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, $\frac{3x6-5}{6-5}$ > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < $\frac{5}{3}$ and x > 5

Answer: x < $\frac{5}{3}$ and x > 5

3 0

3 years ago