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Tomtit [17]
3 years ago
13

If you owned a business, what are some of the ways you could follow green computing recommendations with regards to recycling an

d disposing of old equipment?
Engineering
1 answer:
krek1111 [17]3 years ago
8 0

Answer: E-cycle used computer equipment. Recycle Printer Cartridges and Drum Units. Properly Dispose of Old Technology.

Hope this helps!

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A cylindrical tank is required to contain a gage pressure 520 kPa . The tank is to be made of A516 grade 60 steel with a maximum
enot [183]

Answer:

t= 4.5 mm

Explanation:

Given that

P = 520 KPa ( gauge)

Maximum allowable normal stress ,σ= 150

d= 2.6 m

Wall thickness = t

The normal stress for pressure vessel given as

\sigma=\dfrac{Pd}{2t}               ( hoop stress)

We always take maximum stress for safe design.

\sigma=\dfrac{Pd}{2t}

Now by putting the values

150\times 1000=\dfrac{520\times 2.6}{2t}

t= 4.5 mm

So the minimum thickness, t, of the wall is 4.5 mm

4 0
3 years ago
Nơi nào có điện tích thì xung quanh điện tích đó có :
maksim [4K]

Explanation:

sory sorry sorry sorrysorrysorry

4 0
2 years ago
A pipe 100 mm dia and 1 km long is to carry water from a reservoir to a village of 1000 people consuming 200 l/person/day. The p
natka813 [3]

Answer:

i899999999999999999ijhhh

Explanation:

8 0
3 years ago
Read 2 more answers
What is the power of a parallel circuit with a resistance of 1,000 omh and current of 0.03a
Sergeeva-Olga [200]

Answer: P = I2R = 0.032 x 1000 =0.9 W

Explanation: The power will be the product of the square of the current and

the resistance of the load. The fact that the circuit is a parallel  circuit is irrelevant to this question.

4 0
3 years ago
t is desired to produce aligned carbon fiber-epoxy matric composite having a longitudinal tensile strength of 800 MPa. Given (a)
Nesterboy [21]

Answer:

The value of critical length = 3.46 mm

The value of volume of fraction of fibers = 0.43

Explanation:

Given data

\sigma_{T} =  800 M pa

D = 0.017 mm

L = 2.3 mm

\sigma_{f} = 5500 M pa

\sigma_{m} = 18 M pa

\sigma_c = 13.5 M pa

(a) Critical fiber length is given by

L_{c} = \sigma_{f} (\frac{D}{2 \sigma_{c} } )

Put all the values in above equation we get

L_{c} =5500 (\frac{0.017}{(2) (13.5)} )

L_{c} = 3.46 mm

This is the value of critical length.

(b).Since this  critical length is greater than fiber length Than the volume fraction of fibers is given by

V_{f} = \frac{\sigma_T - \sigma_m}{\frac{L\sigma_c}{D} - \sigma_m }

Put all the values in above formula we get

V_{f} = \frac{800-18}{\frac{(2.3)(13.5)}{0.017} - 18 }

V_{f} = 0.43

This is the value of volume of fraction of fibers.

3 0
3 years ago
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