Air enters a tank through an area of 0.2 ft2 with a velocity of 15 ft/s and a density of 0.03 slug/ft3. Air leaves with a veloci
ty of 5 ft/ s and a density equal to that in the tank. The initial density of the air in the tank is 0.02 slug/ft3. The total tank volume is 20 ft3 and the exit area is 0.4 ft2. Find the initial rate of change of density in the tank.
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Answer :
The number of gold atoms in nanogram is,
The number of gold atoms in picogram is,
Explanation :
As we know that the molar mass of gold is, 196.97 g/mole. That means, 1 mole of gold has 196.97 grams of mass of gold.
As we know that,
1 mole contains number of atoms.
First we have to determine the number of gold atoms in a nanogram.
As, 196.97 grams of gold contains number of gold atoms
And, 1 grams of gold contains number of gold atoms
So, nanograms of gold contains
number of gold atoms
The number of gold atoms in nanogram is,
Now we have to determine the number of gold atoms in a picogram.
As, 196.97 grams of gold contains number of gold atoms
And, 1 grams of gold contains number of gold atoms
So, picograms of gold contains
number of gold atoms
The number of gold atoms in picogram is,