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Delvig [45]
2 years ago
9

Technician A says power steering pumps can be engine driven. Technician B says power steering

Engineering
1 answer:
ELEN [110]2 years ago
7 0

Answer:

The correct option is;

C. Both A and B

Explanation:

Power steering supplies power more steering power when a driver turns the wheel to leverage the input steering effort of the driver thereby providing more steering with small effort

The power steering pumps which supply the power that to the fluid that eases steering of the wheel can be driven by the engine through a belt and pulley system or it can be installed in the front of the vehicle and from there, electrically driven alongside the refrigerant compressor

Therefore, both Technician A and Technician B are correct

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A 860 kΩ resistor has 34 μA of current. What is the supply voltage for this electric circuit?
Juliette [100K]

Explanation:

first changing kilo ohm to ohm

860000 = 860 kΩ

and change 34 micro ampare to ampare

34 μA=3.4×10^-5

recalling the equation V=I*R

V= 3.4×10^-5×860000

v=29.24

8 0
3 years ago
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Describe a gear train that would transform a counterclockwise input rotation to a counterclockwise output rotation where the dri
masya89 [10]

Answer:

For a gear train that would train that transform a counterclockwise input into a counterclockwise output such that the gear that is driven rotates three times when the driver rotates once, we have;

1) The number of gears in the gear train = 3 gears with an arrangement such that there is a gear in between the input and the output gear that rotates clockwise for the output gear to rotate counter clockwise

2) The speed ratio of the driven gear to the driver gear = 3

Therefore, we have;

Speed \ Ratio =\dfrac{Speed \ of \ Driven \ Gear}{Speed \ of \ Driver \ Gear} = \dfrac{The \ Number \ of \ Teeth \ of \ Driver \ Gear}{The \ Number \ of \ Teeth \ of \ Driven \ Gear}

Therefore, for a speed ratio of 3, the number of teeth of the driver gear, driving the output gear, must be 3 times, the number of teeth of the driven gear

Explanation:

3 0
3 years ago
You are given a noninverting 741 op-amp with a dc-gain of 23.6 dB. The input signal to this amplifier is;Vin(t) = (0.18)∙cos(2π(
Vsevolod [243]

Answer:

Output voltage equation is V_{out} (t) = 2.72 \cos (2\pi (57000)t +18.3)

Explanation:

Given:

dc gain A = 23.6 dB

Input signal V_{in} (t) = 0.18 \cos (2\pi (57000)t +18.3)

Now convert gain,

A = 10^{\frac{23.6}{20} } = 15.13

DC gain at frequency f = 0 is given by,

  A = \frac{V_{out} }{V_{in} }

V_{out} =AV_{in}

V_{out} = 15.13 \times   0.18 \cos (2\pi (57000)t +18.3)

At zero frequency above equation is written as,

V_{out} = 2.72 \times \cos 18.3

V_{out} = 2.72

Now we write output voltage as input voltage,

V_{out} (t) = 2.72 \cos (2\pi (57000)t +18.3)

Therefore, output voltage equation is V_{out} (t) = 2.72 \cos (2\pi (57000)t +18.3)

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