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aliina [53]
4 years ago
9

The most basic difference between elliptical galaxies and spiral galaxies is that ________.

Physics
1 answer:
USPshnik [31]4 years ago
7 0
Alliptical galaxies lack anything resembling the disk of a spiral galaxy.



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When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less dam
Lesechka [4]

Answer:

0.55 m/s

Explanation:

Parameters given:

Mass of lighter car, m = 1400 kg

Mass of heavier car, M = 1850 kg

Initial speed of lighter car, u = -1.10 m/s (since it's moving to the left)

Initial speed of heavier car, U = 1.5 m/s

Final sped of heavier car, V = 0.25 m/s

Using the principle of conservation of momentum, total initial momentum is equal to total final momentum:

m*u + M*U = m*v + M*V

Inputting the values:

(1400 * -1.1) + (1850 * 1.5) = (1400 * v) + (1850 * 0.25)

-1540 + 2775 = 1400v + 462.5

1235 = 1400v + 462.5

1400v = 772.5

v = 772.5/1400

v = 0.55 m/s

4 0
4 years ago
Two waves can share the same space and pass through one another. What type of interference occurs when the crests of one wave ov
bulgar [2K]

Question 25 Answer: Destructive interference occurs.

<span>Question 26Answer: The waves are closer together (as they move) because the object is moving toward you.</span>

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4 0
3 years ago
What is the study of sound waves called?<br><br> short answer pls
sweet [91]

Answer:

Acoustics

Explanation: It’s the branch of physics that deals with the study of mechanical waves in gases, liquids, and solids including topics such as vibration, sound, ultrasound and infrasound.

7 0
3 years ago
Read 2 more answers
The asteroid belt circles the sun between the orbits of mars and jupiter. one asteroid has a period of 5.0 earth years. assume a
My name is Ann [436]
Using Kepler's 3rd law which is: T² = 4π²r³ / GM 
Solved for r : 
r = [GMT² / 4π²]⅓ 
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds : 
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s 
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m 
8 0
3 years ago
Read 2 more answers
A 60kg block is at rest on a ramp inclined at 35 degrees.
weeeeeb [17]

Answer:

Explanation:

(a)Gravitational Force is W=mg

Frictional force is f

Normal force is N

(b)Since the block is in Equilibrium therefore from diagram we can see that  

f=mg\sin \theta

f=60\times 9.8\times \sin 35

f=337.26 N

(c)Magnitude of Normal Force

N=mg\cos \theta =481.66 N

(d)friction is also given by

f=\mu mg\cos \theta

and f=mg\sin \theta

thus tan \theta =\mu

\mu =0.7  

8 0
3 years ago
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