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never [62]
3 years ago
11

Hallar la energía mecánica de un pendulo , en un punto de su oscilación donde la energía cinética es 0,39 J y en ese mismo punto

su energía potencial es 0,59 J ?
Physics
1 answer:
iris [78.8K]3 years ago
7 0

Answer:

E = 0,39 + 0,59 = 0,98 J

Explanation:

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Matter and energy can convert into each other. True False
Valentin [98]

the answer is True you can convert matter and energy

8 0
3 years ago
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A foot is 12 inches and a mile is 5280I ft exactly. A centimeter is exactly 0.01m or mm. Sammy is 5 feet and 5.3tall. what is Sa
julia-pushkina [17]

Answer:

65.3 Inches tall

Explanation:

If Sammy is 5 feet and 5.3 inches tall, we simply need to convert the feet to inches, and sum the remaining inches from his height to determine his overall height in inches.

So, 5 feet = (12 inches/1foot) * (5 feet) = 60 inches

And 60 inches + 5.3 inches = 65.3 inches.

Hence, Sammy is 65.3 inches tall.

Cheers.

4 0
3 years ago
2. **A bird is flying south for the winter and mies a total o
dimulka [17.4K]

Answer:

Explanation:

By definition we get that,

velocity = displacement change/ time taken

So for bird we can use,

velocity of the bird = displacement change/ time taken

= 8000/4 = 2000 miles per day =326.61 m/s

3 0
3 years ago
The oil level in a tank is 2 m above the ground. The tank cover is air tight and the air pressure above the oil surface is 150 k
Andrew [12]

Answer:

a) 24.692 m/s

b) 19.4 m

Explanation:

To calculate the velocity at the nozzle outflow (V2) we use the Bernoulli equation:

\frac{P1}{pg}+\frac{V1^2}{2g}+Z1=\frac{P2}{pg}+\frac{V2^2}{2g}+Z2

We know that the velocity above the oil surface (V1) and the pressure at the nozzle outflow (P2) are negligible, the height in the exit is zero (Z2) then:

\frac{P1}{pg}+Z1=\frac{P2}{pg}+\frac{V2^2}{2g}

a) The velocity (V2) is:

\frac{P1}{pg}+Z1=\frac{V2^2}{2g}

(\frac{P1}{pg}+Z1)(2g)=V2^2

V2=[(\frac{P1}{pg}+Z1)(2g)]^{1/2}

Substituting the known values we can get the velocity at the out:

Atmospheric pressure= 101000 Pa

Oil density= 0.88x(Water density)=0.88(1000kg/m3)=880kg/m3

V2=[(\frac{150000Pa+101000 Pa}{(880 kg/m3)(9.81m/s)}+2m)(2(9.81m/s2))]^{1/2}

V2=24.692 m/s

b) To calculate the height we have to apply the Bernoulli equation between the outflow and the maximum height (Z3), so:

\frac{P2}{pg}+\frac{V2^2}{2g}+Z2=\frac{P3}{pg}+\frac{V3^2}{2g}+Z3

We know that the velocity above the stream (V3) and the pressure at the nozzle outflow (P2) are negligible, the pressure at the top of the stream (P3) is the atmospheric pressure, then:

\frac{V2^2}{2g}=\frac{P3}{pg}+Z3

Z3=\frac{V2^2}{2g}-\frac{P3}{pg}

Substituting the known values, the height (Z3) is:

Z3=\frac{(24.692 m/s)^2}{2(9.81 m/s2)}-\frac{101000 Pa}{(9.81 m/s)(880 kg/m3)}

Z3=Maximum Height=19.376=19.4 m

3 0
4 years ago
A high frequency sound wave corresponds to high _____.
lina2011 [118]
A highly frequency sound wave corresponds to a high pitch sound
6 0
3 years ago
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