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3 years ago

What is the value of x? Enter your answer in the box. 2 4

Mathematics

1 answer:

olasank [31]3 years ago

4 0

Hi,

The total degrees in a pentagon is 540. So add all the interior angles we have so far and we get 456. So we then take 540 and subtract the sum of the interior angles to get 84 degrees.

Have a great day!

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If you get it right I will give a brainlist

leva [86]

Answer:

Flour 5, 10, 15, 20

Sugar 4, 8, 12, 16

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.

serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that $p = 0.16$

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136
$

0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

$E = \frac{n}{p}$

In this question, $n = 1, p = 0.16$ . So

$E = \frac{1}{0.16} = 6.25$

The expected number of at-bats until the next home run is 6.25.

6 0

3 years ago

You are rolling two dice at the same time. What is the probability of rolling a sum of 5 or 9?

baherus [9]

You can get a 5 by rolling :
1 and 4
2 and 3
3 and 2
4 and 1

You can get a 9 by rolling :
3 and 6
4 and 5
5 and 4
6 and 3

There are 36 possible outcomes, hence your probability is $\frac{4\cdot2}{36}=\boxed{\frac29}$