The exterior angles of a polygon all add to 360, if you need to find an exterior angle when given the number of sides and that all angles are equal you simply do: 360/ number of sides.
When you need to find the exterior angle when given an interior angle, you do: 180- interior angle.
Hope this helps :)
Answer:
1.50S + 2.50P > 20
Step-by-step explanation:
Answer:
Claim 2
Step-by-step explanation:
The Inscribed Angle Theorem* tells you ...
... ∠RPQ = 1/2·∠ROQ
The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.
... 2·∠RPQ = ∠ROQ
The symmetric property of equality says you can rearrange this to ...
... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ
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* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.
You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.
All you have to do is divide each one by its other number. For example, 5.60 for 8 is the same as one for 0.70. We accomplish this by dividing the 5.60 by 8.
So...
0.70
0.80
0.90
0.75
The first choice is the lowest.
6x-8y=48
to find the x intercept set y=0
6x - 8*0 = 48
6x = 48
divide by 6 on each side
x =48/6
x=8
(8,0)
to find the y intercept set x=0
6(0) - 8y = 48
0 - 8y = 48
-8y = 48
divide by -8 on each side
y = -6
(0,-8)
