Answer:
<em>The temperature will be greater than 25°C</em>
Explanation:
In an adiabatic process, heat is not transferred to or from the boundary of the system. The gain or loss of internal heat energy is solely from the work done on the system, or work done by the system. The work done on the system by the environment adds heat to the system, and work done by the system on its environment takes away heat from the system.
mathematically
Change in the internal energy of a system ΔU = ΔQ + ΔW
in an adiabatic process, ΔQ = 0
therefore
ΔU = ΔW
where ΔQ is the change in heat into the system
ΔW is the work done by or done on the system
when work is done on the system, it is conventionally negative, and vice versa.
also W = pΔv
where p is the pressure, and
Δv = change in volume of the system.
In this case,<em> work is done on the gas by compressing it from an initial volume to the new volume of the cylinder. The result is that the temperature of the gas will rise above the initial temperature of 25°C </em>
Answer:
Option (d) MEP and IHP
Explanation:
MEP stands for Mean Effective Pressure and IHP stands for Indicated Horse Power
In engines (Internal Combustion), engine indicator is generally to indicate the indicate the changes in pressure inside the cylinder of an Internal Combustion Engine or IC engines. Once, Mean Effective Pressure of the engine is calculated it further helps to calculate the Horse power and both these quantities, i.e., MEP and IHP are displayed on the engine indicator.
Answer:
The pipe is open ended and the length of pipe is 3.4 m.
Explanation:
For identification of the type of pipe checking the successive frequencies in both the open pipe and closed pipe as below
Equation for nth frequency for open end pipe is given as
![f_n=\frac{nv}{2L}](https://tex.z-dn.net/?f=f_n%3D%5Cfrac%7Bnv%7D%7B2L%7D)
For (n+1)th value the frequency is
![f_{n+1}=\frac{(n+1)v}{2L}](https://tex.z-dn.net/?f=f_%7Bn%2B1%7D%3D%5Cfrac%7B%28n%2B1%29v%7D%7B2L%7D)
Taking a ratio of both equation and solving for n such that the value of n is a whole number
![\frac{f_{n+1}}{f_n}=\frac{\frac{(n+1)v}{2L}}{\frac{nv}{2L}}\\\frac{350}{300}=\frac{(n+1)}{n}\\350n =300n+300\\50n =300\\n =6\\](https://tex.z-dn.net/?f=%5Cfrac%7Bf_%7Bn%2B1%7D%7D%7Bf_n%7D%3D%5Cfrac%7B%5Cfrac%7B%28n%2B1%29v%7D%7B2L%7D%7D%7B%5Cfrac%7Bnv%7D%7B2L%7D%7D%5C%5C%5Cfrac%7B350%7D%7B300%7D%3D%5Cfrac%7B%28n%2B1%29%7D%7Bn%7D%5C%5C350n%20%3D300n%2B300%5C%5C50n%20%3D300%5C%5Cn%20%3D6%5C%5C)
So n is a whole number this means that the pipe is open ended.
For confirmation the nth frequency for a closed ended pipe is given as
![f_n=\frac{(2n+1)v}{4L}](https://tex.z-dn.net/?f=f_n%3D%5Cfrac%7B%282n%2B1%29v%7D%7B4L%7D)
For (n+1)th value the frequency is
![f_{n+1}=\frac{(2n+3)v}{4L}](https://tex.z-dn.net/?f=f_%7Bn%2B1%7D%3D%5Cfrac%7B%282n%2B3%29v%7D%7B4L%7D)
Taking a ratio of both equation and solving for n such that the value of n is a whole number
![\frac{f_{n+1}}{f_n}=\frac{\frac{(2n+3)v}{2L}}{\frac{(2n+1)v}{2L}}\\\frac{350}{300}=\frac{(2n+3)}{(2n+1)}\\700n+350 =600n+900\\100n =550\\n =5.5\\](https://tex.z-dn.net/?f=%5Cfrac%7Bf_%7Bn%2B1%7D%7D%7Bf_n%7D%3D%5Cfrac%7B%5Cfrac%7B%282n%2B3%29v%7D%7B2L%7D%7D%7B%5Cfrac%7B%282n%2B1%29v%7D%7B2L%7D%7D%5C%5C%5Cfrac%7B350%7D%7B300%7D%3D%5Cfrac%7B%282n%2B3%29%7D%7B%282n%2B1%29%7D%5C%5C700n%2B350%20%3D600n%2B900%5C%5C100n%20%3D550%5C%5Cn%20%3D5.5%5C%5C)
As n is not a whole number so this is further confirmed that the pipe is open ended.
Now from the equation of, with n=6, v=340 m/s and f=300 Hz
![f_n=\frac{nv}{2L}\\300=\frac{6 \times 340}{2L}\\L=\frac{2040}{600}\\L=3.4 m](https://tex.z-dn.net/?f=f_n%3D%5Cfrac%7Bnv%7D%7B2L%7D%5C%5C300%3D%5Cfrac%7B6%20%5Ctimes%20340%7D%7B2L%7D%5C%5CL%3D%5Cfrac%7B2040%7D%7B600%7D%5C%5CL%3D3.4%20m)
The value of length is 3.4m.
Answer:
True reading a bike would be an example of procedural memory
Answer:
2,200 watts
Explanation:
volts x amps = watts
I'm hoping that's what you asked for, otherwise I dont know.