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fgiga [73]
4 years ago
13

Explain why surface temperature increases when two bodies are rubbed against each other. What is the significance of temperature

rise due to friction?
Engineering
1 answer:
Ronch [10]4 years ago
7 0

Answer:

The surface temperature increases when two bodies are rubbed against each other due to friction.

Explanation:

No object has a perfectly even surface. So, when two bodies with uneven surfaces are rubbed against each other, they experience friction.

Friction is a resistance experienced by the two bodies when they are moved against each other.

The friction between the two surfaces, converts the kinetic energy of the movement to the thermal energy.

Thus, resulting in rise in the surface temperature of the two bodies.

Therefore, when two bodies are rubbed against each other, the surface temperature increases due to friction.

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The moons light-colored highlights are
gulaghasi [49]
The light colored material in areas of the mood is the earliest crust on the moon.
3 0
3 years ago
Air at 400 kPa, 980 K enters a turbine operating at steady state and exits at 100 kPa, 670 K. Heat transfer from the turbine occ
AURORKA [14]

Answer:

a) w_{out} = 281.55\,\frac{kJ}{kg}, b) s_{gen} = 0.477\,\frac{kJ}{kg\cdot K}

Explanation:

a) The process within the turbine is modelled after the First Law of Thermodynamics:

-q_{out} - w_{out} + h_{in}-h_{out} = 0

w_{out} = h_{in} - h_{out}-q_{out}

w_{out} = c_{p}\cdot (T_{in}-T_{out})-q_{out}

w_{out} = \left(1.005\,\frac{kJ}{kg\cdot K}\right)\cdot (980\,K-670\,K)-30\,\frac{kJ}{kg}

w_{out} = 281.55\,\frac{kJ}{kg}

b) The entropy production is determined after the Second Law of Thermodynamics:

-\frac{q_{out}}{T_{surr}} + s_{in}-s_{out} + s_{gen} = 0

s_{gen} = \frac{q_{out}}{T_{surr}}+s_{out}-s_{in}

s_{gen} = \frac{q_{out}}{T_{surr}}+c_{p}\cdot \ln\left(\frac{T_{out}}{T_{in}} \right)

s_{gen} = \frac{30\,\frac{kJ}{kg} }{315\,K} + \left(1.005\,\frac{kJ}{kg\cdot K} \right)\cdot \ln\left(\frac{980\,K}{670\,K} \right)

s_{gen} = 0.477\,\frac{kJ}{kg\cdot K}

3 0
3 years ago
Courtney spent $87 at a sporting good store. She spent $29 on a tennis racket and the rest on new shoes How much money did Court
LenKa [72]

Answer

she spent 87-29=$58

8 0
3 years ago
Read 2 more answers
A centrifugal pump is used to extract water from a reservoir at 14,000 gal/min. The pipe connecting the pump inlet to the reserv
Dahasolnce [82]

This question is incomplete, the complete question is;

A centrifugal pump is used to extract water from a reservoir at 14,000 gal/min. The pipe connecting the pump inlet to the reservoir is 12 inches in diameter and is 65 ft long.

The average friction factor in this pipe is 0.018. The pump performance curves indicate that, at this flow rate, the head rise across the pump is 320 ft, the efficiency is 81% and the required NPSH is 25 ft.

Please estimate: The required brake horsepower.

Answer:

The required brake horsepower is 1400.08

Explanation:

Given the data in the question;

Power required to drive the pump can be determined using the formula;

P = r_wQH / η₀(0.745)

given that; centrifugal pump is used to extract water from a reservoir at 14,000 gal/min.

Q = 14,000 gal/min = ( 14,000 × 0.00006309 )m³/sec = 0.883 m³/sec

the head rise across the pump is 320 ft,

H = 320 ft = ( 320 × 0.3048 )m = 97.536 m

the efficiency η₀ = 81% = 0.81

r_w = 9.81 kN/m³

so we substitute our values into the formula

P = [ 9.81 × 0.883 × 97.536 ] / 0.81(0.745)

P = 844.87926528 / 0.60345

P = 1400.08 HP

Therefore, The required brake horsepower is 1400.08

5 0
3 years ago
An alloy to be used for a spring application must have a modulus resilience of at least 0.79 x 106 J/m3 (0.79 x 106 Pa). What mu
xxTIMURxx [149]

Answer:

4.13 MPa

Explanation:

Given

Modulus of elasticity = E = 102 GPa

E = 102 * 10^9

Modulus resilience U = 0.79 * 106Pa

Modulus of Resilience U = y²/2E --- Make y the subject of formula

y² = 2EU

y = √(2EU)

y = √(2 * 102 * 10^9 * 0.79 * 106)

y = √1.708296E13

y = 4133153.759540044

y = 4.13E6

y = 4.13MPa

3 0
3 years ago
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